In order to get the number of moles of a substance when given the mass of the substance you must divide the mass in grams by the molar mass of the substance, which for aluminum is 26.98. So the answer is 27/26.98 = 1.0007, which would be rounded to 1.0 mol.
1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
2,89 moles of aluminium contain 17,40398707673.1023 atoms.
0.0845 moles of tungsten is equal to 0,50887.10e23.
6.3x10^24 aluminum atoms represent 1 mole of aluminum atoms because Avogadro's number is approximately 6.022x10^23.
There are approximately 1.93 x 10^24 atoms in 3.20 moles of aluminum. This calculation is based on Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, ions, etc.).
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
2,89 moles of aluminium contain 17,40398707673.1023 atoms.
To find the number of aluminum atoms in 30 grams, you first need to determine the number of moles of aluminum using its molar mass (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
In one mole of aluminum III oxide (Al2O3), there are 2 moles of aluminum atoms (since there are 2 aluminum atoms in each formula unit of Al2O3) and 3 moles of oxygen atoms. Therefore, one mole of aluminum III oxide contains 2 + 3 = 5 moles of atoms. Avogadro's number (6.022 x 10^23) of atoms can be found in one mole of any substance.
To find the number of moles, you first need to convert the number of atoms to moles using Avogadro's number, which is 6.022 x 10^23 atoms/mol. Then divide the given number of atoms by Avogadro's number to get the answer.
To determine the number of moles of aluminum present, we need to first determine the molar mass of aluminum, which is approximately 26.98 g/mol. We can then use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 15 g / 26.98 g/mol ≈ 0.56 moles of aluminum.
Answer: 8.6 Mol. To Find this you need to set up your dimensional analysis as: (5.2x1024atoms)(1 mol/6.022x1023atoms)= 8.6 Mol. Your atoms cancel out, so finish working the math out and your left with moles of Aluminum.
0.0845 moles of tungsten is equal to 0,50887.10e23.
6.3x10^24 aluminum atoms represent 1 mole of aluminum atoms because Avogadro's number is approximately 6.022x10^23.
There are approximately 1.93 x 10^24 atoms in 3.20 moles of aluminum. This calculation is based on Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, ions, etc.).