For this you need the Atomic Mass of Hg. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.
12.0 moles Hg × 200.6 grams = .0598 grams Hg
How many moles are there in 9.0333x1024 atoms of helium
1 mole has 6.023 x 1023 atoms So, in 3.05 moles there are 18.37 x 1023 atoms
To find the number of moles of helium, you can use Avogadro's number, which is approximately (6.02 \times 10^{23}) atoms per mole. Divide the total number of helium atoms ( (6.02 \times 10^{25}) atoms) by Avogadro's number: [ \text{Moles of helium} = \frac{6.02 \times 10^{25} \text{ atoms}}{6.02 \times 10^{23} \text{ atoms/mole}} \approx 100 \text{ moles}. ] Thus, there are about 100 moles of helium in the balloon.
There are approximately 2.8 x 10^24 atoms in 4.7 moles of helium. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mole) by the number of moles (4.7).
using the formula: n=m/gfm no. of moles=mass/gfm you take the gram formula mass (gfm) as 4. and given the mass is 16g, both numbers can be substituted into the formula... n=16/4 = 4 the number of moles present in 16g of helium is 4 moles.
How many moles are there in 9.0333x1024 atoms of helium
1 mole has 6.023 x 1023 atoms So, in 3.05 moles there are 18.37 x 1023 atoms
To find the number of moles of helium, you can use Avogadro's number, which is approximately (6.02 \times 10^{23}) atoms per mole. Divide the total number of helium atoms ( (6.02 \times 10^{25}) atoms) by Avogadro's number: [ \text{Moles of helium} = \frac{6.02 \times 10^{25} \text{ atoms}}{6.02 \times 10^{23} \text{ atoms/mole}} \approx 100 \text{ moles}. ] Thus, there are about 100 moles of helium in the balloon.
There are approximately 2.8 x 10^24 atoms in 4.7 moles of helium. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mole) by the number of moles (4.7).
To find the number of helium atoms in 542 kg of helium, you need to first calculate the number of moles of helium in 542 kg using the molar mass of helium, which is 4 grams/mol. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of helium to atoms.
The number of helium atoms (not molecules) is 39,7945.10e23.
using the formula: n=m/gfm no. of moles=mass/gfm you take the gram formula mass (gfm) as 4. and given the mass is 16g, both numbers can be substituted into the formula... n=16/4 = 4 the number of moles present in 16g of helium is 4 moles.
To find the number of helium atoms, we need to convert the mass of helium to moles and then use Avogadro's number to convert moles to atoms. The molar mass of helium is 4 g/mol. First, convert 590 kg to grams (590,000 g). Then, divide by the molar mass of helium to find moles, and finally multiply by Avogadro's number (6.022 x 10^23 atoms/mol) to get the number of atoms.
use this formula, n(He)=m(He)/M(molar mass of He) =0.255G/4.OO =0.06375 moles per gram.
1 mole = 6.0 x 1023 atomsSo, 4 mole = 24 x 1023 atoms or 2.4 x 1024 atoms
.7 g= .17 mol = 1.05 x 10^23 atoms
For this you need the atomic (molecular) mass of H2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.3.00 moles H2 × 2.02 = 6.06 grams H2