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Quinine has the chemical formula C20H24N2O2. To determine the number of moles of hydrogen in 1.8 moles of quinine, we note that each molecule of quinine contains 24 hydrogen atoms. Therefore, in 1.8 moles of quinine, there are 1.8 moles × 24 moles of hydrogen = 43.2 moles of hydrogen.
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How many moles of carbon and hydrogen are there in 5 moles of octane?
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
5.8 grams in 1 liter of water equals how many moles?
To convert grams to moles, divide the mass in grams by the molar mass of the substance. The molar mass of water is approximately 18 g/mol (1 g/mol for hydrogen and 16 g/mol for oxygen). So, 5.8 grams of water in 1 liter would be approximately 0.32 moles (5.8 g / 18 g/mol).
A sample of 90 g water was decomposed using electrolysis How many liters of hydrogen where produced at STP?
The molar mass of water is 18 g/mol. Since there are 2 hydrogen atoms in each water molecule, the molar mass of hydrogen is 2 g/mol. Therefore, 90 g of water contains 5 moles of water, which means 10 moles of hydrogen were produced. At STP, 1 mole of any gas occupies 22.4 liters, so 10 moles of hydrogen would occupy 224 liters.
How many grams of hydrogen are in 25.0g of water?
25x(2/18)=2.78g of hydrogen 25x(16/18)=22.22g of oxygen
18 l of ammonia were produced by the haber process how many liters of hydrogen were used during the reaction the reaction took place at stp 0ºc and 1.0 atm n2 g plus 3 h2 g --2 nh3 g?
According to the balanced chemical equation, 3 moles of hydrogen are required to produce 2 moles of ammonia. As 22.4 liters of any gas at STP is equal to 1 mole, 1 mole of hydrogen gas occupies 22.4 liters. Therefore, to produce 18 liters of ammonia, (18/22.4) x 3 = 2.68 moles of hydrogen were used. This equates to 2.68 x 22.4 = 60.03 liters of hydrogen gas used during the reaction.
How many moles of H are in 2 mol of c8h18?
2 moles C8H18 (18 moles H/1 mole C8H18) = 36 moles of hydrogen =================
How many moles of ammonia can be produced from 18 moles of hydrogen?
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
How many moles of carbon and hydrogen are there in 5 moles of octane?
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
How many moles of hydgrogen are needed to produce 6.0 moles of ammonia?
This is based on calculations too. It contains 18 hydrogen moles.
How many grams of water are produced when 2.5 mil oxygen reacts with hydrogen?
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
How many moles of water are present 180 grams of water?
To find the number of moles in 180 grams of water, divide the mass by the molar mass of water. The molar mass of water is approximately 18 g/mol (2*1 (hydrogen) + 16 (oxygen)). So, 180g ÷ 18 g/mol = 10 moles of water.
How many grams of water can be prepared from 5moles of hydrogen at standard conditions?
At standard conditions, 1 mole of hydrogen reacts with 0.5 moles of oxygen to form 1 mole of water. Therefore, to form 5 moles of water, you will need 5 moles of hydrogen and 2.5 moles of oxygen. The molar mass of water is approximately 18 g/mol, so 5 moles of water would weigh 90 grams.
How many grams of water are made from complete reaction of 2.2 moles of oxygen gas with hydrogen gas?
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
How many grams of hydrogen are needed to produce 30.0 grams of water?
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
5.8 grams in 1 liter of water equals how many moles?
To convert grams to moles, divide the mass in grams by the molar mass of the substance. The molar mass of water is approximately 18 g/mol (1 g/mol for hydrogen and 16 g/mol for oxygen). So, 5.8 grams of water in 1 liter would be approximately 0.32 moles (5.8 g / 18 g/mol).
A sample of 90 g water was decomposed using electrolysis How many liters of hydrogen where produced at STP?
The molar mass of water is 18 g/mol. Since there are 2 hydrogen atoms in each water molecule, the molar mass of hydrogen is 2 g/mol. Therefore, 90 g of water contains 5 moles of water, which means 10 moles of hydrogen were produced. At STP, 1 mole of any gas occupies 22.4 liters, so 10 moles of hydrogen would occupy 224 liters.
How many grams of hydrogen are in 25.0g of water?
25x(2/18)=2.78g of hydrogen 25x(16/18)=22.22g of oxygen
