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How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many moles potassium chlorate must be used to produce 6 moles of oxygen gas?
We need 3 moles of potassium perchlorate.
How many moles of potassium chlorate must be used to produce 6 moles if oxygen gas?
Four moles of potassium chlorate are needed.
How many moles of Co2 will be produced from the reaction of three moles of acetylene with excess oxygen?
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
How many moles of cesium chlorate must be decomposed to produce 2.7 moles of oxygen gas?
To find the moles of cesium chlorate needed to produce 2.7 moles of oxygen gas, use the balanced chemical equation for the decomposition of cesium chlorate: 2CsClO3 -> 2CsCl + 3O2 From the equation, it shows that 2 moles of cesium chlorate produce 3 moles of oxygen gas. Therefore, you will need (2/3) * 2.7 = 1.8 moles of cesium chlorate to produce 2.7 moles of oxygen gas.
How many moles of potassium chlorate (KClo3) must be used to produce 6 moles of oxygen?
2KClO3==>2KCl+3O2 is the equation. so you need 4 moles of KClO3.
How many moles of oxygen are produced from 14 moles of potassium chlorate?
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
How many moles of potassium chlorate produce 6 moles of oxygen gas?
The chemical reactin is:2 KClO3 = 2 KCl + 3 O24 moles of potassium chlorate produce 6 moles oxygen.
How many moles of oxygen are produced from twelve moles of potassium chlorate?
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
How many moles of KCl will be formed from 0.440 moles of KClO3?
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
How many moles of potassium chlorate are needed to produce 15 moles of oxygen?
For the decomposition of potassium chlorate, the molar ratio between potassium chlorate (KClO3) and oxygen (O2) is 2:3. Therefore, to produce 15 moles of oxygen, 10 moles of potassium chlorate are needed. (15 moles O2) x (2 moles KClO3 / 3 moles O2) = 10 moles KClO3.
How many moles of KClO3 on decomposition give 1 mole of oxygen?
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
How many moles of oxygen are produced when 7.5 moles of potassium chlorate decompose completely?
For every mole of potassium chlorate that decomposes, three moles of oxygen are produced. Therefore, if 7.5 moles of potassium chlorate decompose, 22.5 moles of oxygen would be produced (7.5 moles x 3).
How many moles of oxygen would be produced by 1.2 moles of KClO3?
2 to 3, because of the balanced equation:2 KClO3 --> 2 KCl + 3 O2
When 46.0 g KClO3 is heated 12.1 g O2 is formed how many grams of KCl is also formed?
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
