It loses 2 electrons to obtain the argon configuration of 8 valence electrons.
The calcium atom (Ca) loses two valence electrons to form a calcium ion (Ca2+).
Calcium loses 2 valence electron to become ionized.
Sulfur has 6 valence electrons. To achieve 8 valence electrons, sulfur must gain 2 electrons to fill its outer shell and satisfy the octet rule.
It will lose 2 electrons.
Sulfur must gain two electrons.
The valence electrons of calcium will tend to give away electrons, as it is an alkaline earth metal with two valence electrons. This makes it more energetically favorable for calcium to lose these two electrons and achieve a full outer electron shell by forming a 2+ cation.
Calcium would need to lose 2 electrons to have 8 valence electrons. This is because calcium has 2 valence electrons in its outer shell, and by losing these 2 electrons, it can achieve a stable octet configuration like the noble gas argon.
A calcium atom must lose 2 electrons to have 8 valence electrons, achieving a full outer shell and stability. Calcium is in group 2 of the periodic table, so it has 2 valence electrons originally. By losing 2 electrons, it will have a stable electron configuration similar to a noble gas.
The calcium atom (Ca) loses two valence electrons to form a calcium ion (Ca2+).
Calcium loses 2 valence electron to become ionized.
Phosphorus wants to gain three electrons to have 8 valence electrons.
Phosphorus wants to gain three electrons to have 8 valence electrons.
Sulfur has 6 valence electrons. To achieve 8 valence electrons, sulfur must gain 2 electrons to fill its outer shell and satisfy the octet rule.
It will lose 2 electrons.
Sulfur must gain two electrons.
Compounds will gain or lose electrons in order to reach a more stable state, ideally a full valence shell.
Ca must lose 2 electrons to have a complete 3n shell, which has 8 valence electrons. The ion would have a charge of 2+: Ca^2+.