To find the current drawn, use the formula: Current (I) = Power (P) / Voltage (V). Plugging in the values, I = 795 W / 120 V = 6.625 A. Therefore, the appliance draws approximately 6.625 A of current when plugged into a 120 V outlet.
Basically, Power = Current*Voltage Current = Power/Voltage Current = 15/120 Current = 0.125A or 125mA
The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.
To find the resistance necessary, one would need to know how much current the bulb draws. If one knows the current the bulb draws, then one would subtract the 14 volts from 120 volts then divide that by the current the bulb draws and one will find the resistance needed. Once this has been done, one would need to multiply the current drawn by the voltage drop to get the wattage rating necessary. Another important detail to note is that the power dissipated by the resistor will be much greater than the power consumed by the bulb itself. Finally if the bulb burns out the voltage across the contacts will be 120V. I would not recommend using this method to drop the voltage for the bulb.
The in line fan may be drawing too much power for the GFCI outlet to handle, causing it to trip. The outlet may not be faulty; rather, it is doing its job by tripping to prevent electrical hazards. Consider using the in line fan on a different circuit or using a lower wattage fan to prevent further tripping.
To find the current drawn, use the formula: Current (I) = Power (P) / Voltage (V). Plugging in the values, I = 795 W / 120 V = 6.625 A. Therefore, the appliance draws approximately 6.625 A of current when plugged into a 120 V outlet.
The fuse is what restricts how much current you can draw from an outlet. If you have the wrong fuse you can draw more power than intended from an outlet - but only if the appliance plugged in can use it up. To get too much power out of an outlet, with a suitable appliance plugged in, then you also have to have a higher voltage in the outlet. And for that to happen, something has to be seriously wrong higher upp in the supply chain.
Power is multiplication of voltage and current. You need to know the load current drawing to establish the power. It is a bad idea to use 230 v adapter in 120 volts outlet
Basically, Power = Current*Voltage Current = Power/Voltage Current = 15/120 Current = 0.125A or 125mA
A 120V household electrical outlet supplies 12 watts of powerwhen the current is 0.1 Ampere (and the power factor is 100%).
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The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.
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To find the resistance necessary, one would need to know how much current the bulb draws. If one knows the current the bulb draws, then one would subtract the 14 volts from 120 volts then divide that by the current the bulb draws and one will find the resistance needed. Once this has been done, one would need to multiply the current drawn by the voltage drop to get the wattage rating necessary. Another important detail to note is that the power dissipated by the resistor will be much greater than the power consumed by the bulb itself. Finally if the bulb burns out the voltage across the contacts will be 120V. I would not recommend using this method to drop the voltage for the bulb.
No ~ the power supply is capable of supplying 5 Amps, but the device will only draw 1 Amp. Therefore the power supply can still safely supply another 4 Amps if required.AnswerIt's important to understand that the '5 A' referred to in the specification of your power supply is its capacity -the actual current drawn from the power supply is determined by the load you attach to it. So, if your load requires only 1 A, then that's how much current will be drawn from the power supply.