To determine the current required by a 75-W bulb in a 100-W circuit, we first need to know the voltage of the circuit. Assuming a standard voltage of 120 volts, the current can be calculated using the formula ( I = P/V ), where ( P ) is power in watts and ( V ) is voltage in volts. For a 75-W bulb, the current would be ( I = 75 , \text{W} / 120 , \text{V} = 0.625 , \text{A} ). Thus, the 75-W bulb requires approximately 0.625 amperes of current.
The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.
The equation that you are looking for is I = E/R. Amps = Voltage/Resistance in ohms.
To find the resistance necessary, one would need to know how much current the bulb draws. If one knows the current the bulb draws, then one would subtract the 14 volts from 120 volts then divide that by the current the bulb draws and one will find the resistance needed. Once this has been done, one would need to multiply the current drawn by the voltage drop to get the wattage rating necessary. Another important detail to note is that the power dissipated by the resistor will be much greater than the power consumed by the bulb itself. Finally if the bulb burns out the voltage across the contacts will be 120V. I would not recommend using this method to drop the voltage for the bulb.
The 194 bulb is ~3.8 watts, at 14 volts they draw 0.271 amps.
If the current is stronger then the bulb will be brighter.The reading is much easier when you sit under the brighter bulb.
Too much current for the rating of the bulb.
To determine the current required by a 75-W bulb in a 100-W circuit, we first need to know the voltage of the circuit. Assuming a standard voltage of 120 volts, the current can be calculated using the formula ( I = P/V ), where ( P ) is power in watts and ( V ) is voltage in volts. For a 75-W bulb, the current would be ( I = 75 , \text{W} / 120 , \text{V} = 0.625 , \text{A} ). Thus, the 75-W bulb requires approximately 0.625 amperes of current.
how much resistance does a light bulb creat if iyt has a current of 25 mA around it in a 9 V circuit?
That does not depend directly on the brightness of the bulb, it depends on the current drawn by the bulb (which depends on the efficiency of the bulb). For example an incandescent bulb will draw much more current than a much brighter CFL bulb or LED bulb. Therefor switching to an brighter LED bulb can make the battery last much longer while switching to a brighter incandescent bulb will make the battery run down quicker.
The current of one bulb (two bulbs shorted) would be about1 three times the current of three bulbs.1 I say "about" because resistance is a function of temperature, and running three times the current through one bulb will make that one bulb much hotter, increasing its resistance. It might also burn out the bulb.
same current flow in each bulb
To answer this question a voltage must be given.
21
50-Voltage
A 240 v 14 w cfl bulb uses about 0.14 amps.
The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.