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How much heat in joules is needed to raise the temperature of 4.0 L of water from 0 degrees Celsius to 70.0 degrees Celsius?
It takes 4.186 Joules to heat one gram of water by 1-degree Celsius. 4.186 * 4000 = 16,744 Joules to heat 4 kilos of water by 1-degree. 16,744 * 70 = 1,172,080 Joules. The above assumes that one litre of water weighs exactly 1 Kilogram.
What is an amount of energy needed to raise kg of a subsyance1c?
The amount of energy needed to raise the temperature of a substance is calculated using the formula ( Q = mc\Delta T ), where ( Q ) is the heat energy (in joules), ( m ) is the mass of the substance (in kilograms), ( c ) is the specific heat capacity (in joules per kilogram per degree Celsius), and ( \Delta T ) is the change in temperature (in degrees Celsius). This formula helps determine how much energy is required to achieve a desired temperature increase for a given mass of a substance.
How much energy is needed to raise the temperature of 2kg of water by 1ᵒC?
To raise the temperature of 2 kg of water by 1°C, you need 8,400 joules of energy. This is calculated using the specific heat capacity of water, which is approximately 4,200 joules per kilogram per degree Celsius (J/kg°C). Therefore, the energy required is 2 kg × 4,200 J/kg°C × 1°C = 8,400 J.
How much heat is needed to raise 8 kg of water from 4 degress celsius to 83 degrees celsius?
The amount of heat needed to raise the temperature of a substance can be calculated using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the temperature change. Plugging in the values, we get Q = 8 kg * 4186 J/kg°C * (83°C - 4°C) = 2,309,056 Joules. Therefore, 2,309,056 Joules of heat energy is needed to raise 8 kg of water from 4°C to 83°C.
How many joules are needed to raise the temperature of 1 kg of gypsum plaster by 1C?
To calculate the energy needed to raise the temperature of 1 kg of gypsum plaster by 1°C, you can use the specific heat capacity formula: ( Q = mc\Delta T ), where ( m ) is the mass (1 kg), ( c ) is the specific heat capacity of gypsum plaster (approximately 1.2 J/g°C), and ( \Delta T ) is the temperature change (1°C). Converting the specific heat capacity to J/kg°C gives you about 1200 J/kg°C. Therefore, you would need approximately 1200 joules to raise the temperature of 1 kg of gypsum plaster by 1°C.
What is is the amount of heat needed to raise the temperature of one kilogram of water one degree centigrade.?
The specific heat capacity of water is approximately 4.18 Joules per gram per degree Celsius. To raise the temperature of one kilogram (1000 grams) of water by one degree Celsius, it would require approximately 4180 Joules of heat energy.
How much energy is needed to raise the temperature of 2.0 grams of water of 5.0 Celsius?
42 J
The number of kilojoules needed to raise the temperature of 32.0 g of water from 12.0 degree centigrade to 54.0 degree centigrade is?
q(Joules) = mass * specific heat * change in temperature q = 32.0 grams H2O * 4.180 J/gC *(54.0 C - 12.0 C) = 5617.92 Joules this is, of course 5.62 kilojoules
What is the amount of heat needed to raise the temperature of 1kilogram of water 1degrees Celsius?
The specific heat capacity of water is 4.18 J/g°C. Therefore, it would require 4186 Joules (4.18 x 1000 grams) of energy to raise the temperature of 1 kilogram of water by 1 degree Celsius.
What is the amount of heat needed to raise that temperature of 1 kilogram of water 1 degree Celsius?
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.
How many joules are absorbed by the water with a mass of 8 kg in order to raise the temperature from 20 degrees to 70 degrees?
q(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams ) q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C) = 1.7 X 106 joules ============
Joules divided by Celsius times grams?
This calculation is used to find the specific heat capacity of a substance. The specific heat capacity is a measure of how much energy is needed to raise the temperature of a given amount of a substance by 1 degree Celsius. The formula used is: specific heat capacity = energy (in Joules) / (mass (in grams) * change in temperature (in Celsius)).
What is the amount of energy needed to raise the temperature of 1 gram of water by 1 degrees Celsius?
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
Approximately how many Joules of heat are needed to completely change 10.0 grams of ice to water at the melting point temperature?
To completely change 10.0 grams of ice to water at the melting point temperature, we need to calculate the heat required for the phase change from solid to liquid and the heat needed to raise the temperature of the resulting water to the melting point temperature. The heat of fusion for water is 334 J/g, so the heat needed for the phase change is 10.0 g * 334 J/g = 3340 J. The heat needed to raise the temperature of the resulting water to the melting point temperature is calculated using the specific heat capacity of water, which is 4.18 J/g°C. The temperature change is from 0°C to 0°C, so no additional heat is needed for this step. Therefore, the total heat required is 3340 J.
How many kilowatts are needed raise 480 tons of water by 10 degrees centigrade?
First, a kilowatt is a power unit equal to 1000 Joules per second. Raising water temperature, without specifying a timeframe is a question of how much energy is needed. You need to specify how fast you want to raise the temperature to get power kW. A tonne is 1000 kilograms, which is 10^6 grams, so 480 tonnes is 4.8 x 10^8 grams. It takes 1 calorie to raise a gram of water by 1°C, so it takes 10 x (4.8 x 10^8) calories = 4.8 x 10^9 calories. Taking 1 calorie = 4.1868 joules, we have 2.009664 x 10^10 joules, or 20.09664 gigajoules.
How many joules are necessary to raise the temperature of 53.5 grams of water from 16.5 degrees celsius to 70.1 degrees celsius?
Energy is actually given off in the lowering of temperature. Use the equation Q = mc(change in T). In this case, m = 2.9, c = 4.179 J, and change in T = -12.1 degree C. Now solve for Q, the heat energy. This exothermic process gives off approximately 146.6 J of heat.
How many calories of heat needed to raise temperature of 8.1 g of water 20C?
1 calorie is defined as the amount of energy needed to raise the temperature of 1 gram of water by 1C, so... It takes 8.1 calories to raise your 8.1 grams by 1C, but you need to raise it 20C. 8.1*20=162. 162 calories is the answer you are looking for.
