0
What else can I help you with?
How much ice at a temperature of -19.1 C must be dropped into the water so that the final temperature of the system will be 29.0 C?
To calculate the mass of ice needed to raise the temperature of the system, we can use the principle of heat transfer where heat lost by ice = heat gained by water. The heat lost by the ice is m_ice * c_ice * ΔT_ice, and the heat gained by the water is m_water * c_water * ΔT_water. By setting these two equal and solving for m_ice, we can determine the mass of ice needed.
If water temp changes 15 degrees C how much heat was gained by the water?
To calculate the amount of heat gained by the water when the temperature changes by 15 degrees Celsius, you can use the formula: Q = mcΔT, where Q is the heat gained, m is the mass of water, c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the temperature change (15°C).
Explain why the heat gained by the water must be calculated?
Calculating the heat gained by water is essential to understand how much energy is needed to raise its temperature. This calculation helps in determining the amount of heat transfer during a process, such as heating water for cooking or brewing coffee. It is crucial for ensuring that the desired temperature is reached efficiently and safely.
How much heat is lost when 2012 grams of stream at 400 K is changed into ice at 263 K?
To determine the heat lost, we need to calculate the heat required to cool the steam from 400 K to 273 K (its condensation point), then the heat required to change it from steam to liquid water, and finally the heat required to freeze the water into ice at 273 K. These steps involve the specific heat capacities of water and steam, latent heat of vaporization, and latent heat of fusion.
How do you find how much heat is gained in a specific heat problem?
To find the heat gained in a specific heat problem, you can use the formula: Q = mcΔT, where Q is the heat gained, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature. Simply plug in the values for mass, specific heat capacity, and temperature change to calculate the heat gained.
How much heat is absorbed when 500 g of water Cp equals 4184 Jg oC goes from 250 oC to 350 oC?
Heat gained by one object = Heat lost by the other. Does that help?
How much ice at a temperature of -19.1 C must be dropped into the water so that the final temperature of the system will be 29.0 C?
To calculate the mass of ice needed to raise the temperature of the system, we can use the principle of heat transfer where heat lost by ice = heat gained by water. The heat lost by the ice is m_ice * c_ice * ΔT_ice, and the heat gained by the water is m_water * c_water * ΔT_water. By setting these two equal and solving for m_ice, we can determine the mass of ice needed.
If water temp changes 15 degrees C how much heat was gained by the water?
To calculate the amount of heat gained by the water when the temperature changes by 15 degrees Celsius, you can use the formula: Q = mcΔT, where Q is the heat gained, m is the mass of water, c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the temperature change (15°C).
Explain why the heat gained by the water must be calculated?
Calculating the heat gained by water is essential to understand how much energy is needed to raise its temperature. This calculation helps in determining the amount of heat transfer during a process, such as heating water for cooking or brewing coffee. It is crucial for ensuring that the desired temperature is reached efficiently and safely.
How much faster is a divers body heat lost through conduction in water than in air?
A diver's body heat is lost around 25 times faster in water compared to air due to the higher thermal conductivity of water. Water conducts heat more efficiently than air, leading to faster heat loss when submerged in water.
How much heat energy will be lost by a 200 gram mass of water as it cools from 40 degree Celsius to 35 degree Celsius?
The amount of heat energy lost by the water can be calculated using the equation Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the change in temperature (40°C - 35°C). Plugging in the values, you will find the heat energy lost by the water.
How much heat is gained by 50 grams of water if the temperature is raised from 40 c to 95 C?
q = m x C x DT q = amount of heat energy gained or lost in Joules (J) m = mass of sample in grams = 50g C = heat capacity (J/ g•oC) = 4.186J/g•oC for water Tf = final temperature = 95 oC Ti = initial temperature = 40 oC DT = (Tf - Ti) = (95 oC - 40 oC) = 55 oC q = 50g x 4.186J/g•oC x 55 oC = 11511.5 J = 10000 J (rounded to 1 significant figure)
How much water weight is lost in a1 hour workout in 90 degree heat?
No way of telling, as how much you sweat is a very individual thing.
How much heat is lost when 2012 grams of stream at 400 K is changed into ice at 263 K?
To determine the heat lost, we need to calculate the heat required to cool the steam from 400 K to 273 K (its condensation point), then the heat required to change it from steam to liquid water, and finally the heat required to freeze the water into ice at 273 K. These steps involve the specific heat capacities of water and steam, latent heat of vaporization, and latent heat of fusion.
How much heat is added when 22 grams of water are heated from 10 degreesC to 15 degrees C?
(110 calories) plus (heat lost from the container during the procedure)
How much heat is lost by water as 0.250kg cools from 35 degrees Celsius to 20 degrees Celsius?
To calculate the heat lost, you can use the formula Q = mcΔT, where Q is the heat lost, m is the mass of water (0.250 kg), c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the change in temperature (35°C - 20°C = 15°C). First, convert the mass to grams, then calculate the heat lost.
How much heat must be lost by 2 grams of water at 0 degrees Celsius to change it to ice?
The heat lost by water at 0 degrees Celsius to change to ice is equal to the heat of fusion of water, which is about 334 joules per gram. So, for 2 grams of water, the heat loss would be 2 * 334 = 668 joules.
