A mole of any substance contains approximately 6.022 x 10^23 particles. For barium, this would be 6.022 x 10^23 atoms of barium.
The molecular weight of Barium Chromate (BaCrO4) is 253.37.Therefore, one Gram Mole weighs 253.37 grams.When handling this chemical REMEMBER, it is Poisonous!
Molecular weight for Barium is 137.33 amu.
The molar mass of BaSO4 (barium sulfate) is 233.38 g/mol. Therefore, the weight of 1 mole of BaSO4 is 233.38 grams.
The lattice energy of Barium oxide (BaO) is typically around 2760 kJ/mol. It represents the energy released when gaseous ions combine to form one mole of a solid ionic compound.
Barium sulfate is sparingly soluble in water, while barium chloride is more soluble. Barium sulfate has a solubility of about 0.0015 g/100 mL of water at room temperature, while barium chloride is much more soluble at about 36 g/100 mL of water at room temperature.
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
The molecular weight of Barium Chromate (BaCrO4) is 253.37.Therefore, one Gram Mole weighs 253.37 grams.When handling this chemical REMEMBER, it is Poisonous!
A mole of barium chloride, BaCl2, contains 6.022 x 10^23 formula units, and each formula unit contains 1 barium atom (Ba) and 2 chloride atoms (Cl). So, there are 6.022 x 10^23 barium atoms and 2 x 6.022 x 10^23 chloride atoms in a mole of barium chloride.
One mole of anything is approximately 6.022 x 1023 units. So, one mole of Ba would be 6.022 x 1023 atoms. One mole of H would be 6.022 x 1023. And so forth...
Molecular weight for Barium is 137.33 amu.
The molar mass of BaSO4 (barium sulfate) is 233.38 g/mol. Therefore, the weight of 1 mole of BaSO4 is 233.38 grams.
The formula of the hydrate is BaCl2•2H2O. The ratio of barium chloride to water is 1:2, so there are two moles of water for every mole of barium chloride in the compound.
The barium atom has a much bigger radius.
The simplest formula based on the given moles would be BaSO4 (barium sulfate). This is determined by dividing each mole value by the smallest mole value (0.080 mole), resulting in a ratio of 1 Ba : 1 S : 4 O, which corresponds to BaSO4.
Barium nitride is Ba3N2 (from the rules of ionic bonding). Its molar mass is 439 grams/mole (from the periodic table), so 18.8 grams of it is 0.0428 moles (by algebraic direct proportion). Multiply this by Avogadro's number (6.02x1023; the number of particles in 1 mole) and you get 2.58x1022 formula units of barium nitride, and there are 2 nitrogen atoms per formula unit, so double it to 5.16x1022 atoms of nitrogen.
The molar mass of barium (Ba) is approximately 137.3 g/mol. So, the mass of 3 moles of barium would be 3 moles x 137.3 g/mol = 411.9 grams.
The molar mass of barium hydride (BaH2) is 137.33 g/mol. Therefore, the mass of 4.80 mol of barium hydride would be 4.80 mol x 137.33 g/mol = 659.184 g.