To reduce 24 volts DC to 12 volts DC using a resistor, you can use Ohm's Law (V = IR). The required resistance depends on the load current you are working with. For example, if the load draws 1 ampere, you would need a resistor with a value of 12 ohms (R = V/I = 12V/1A). However, using a resistor for voltage regulation is not efficient and can cause power loss; a DC-DC converter is a better solution for reducing voltage in most applications.
Milli volt is one thousandth of a Volt and Milli amp is one thousandth of an Amp. Volt and Amp measure two different things and are not really comparable. Over simplified, here is how it works. Volt measures the 'pressure' that causes current to flow. Current flow is measured in Amps and depends on the how much resistance the 'pressure' has to overcome. Higher the resistance, lesser the current (Amp) for same pressure (Volt)
Usually a volt meter is placed across a component to measure the voltage drop across that component. Doing this places the volt meter resistance in parallel with that component's resistance, which will always lower the total resistance. Since the volt meter resistance is usually very large relative to the resistance of the element being measured, the total resistance does not change significantly. The formula for total resistance of two parallel elements is: Rtot = (R1*R2)/(R1+R2), as R1 (the volt meter) >> R2, Rtot ~= (R1*R2) / (R1) = R2 If a volt meter is placed into a circuit instead of around an element of that circuit, it will raise the resistance of the circuit, load the circuit with, and interrupt "normal" operation of the circuit (normal operation = how things would be without the meter in place). More importantly, the volt meter would then be measuring the voltage developped across itself (instead of an element of the circuit), which is not the point of this tool / this would be a misapplication of a volt meter.
The formulas you are looking for is I = E/R.
To calculate the resistance needed, you can use Ohm's Law: R = V^2 / P, where R is resistance, V is voltage, and P is power. In this case, R = (3^2) / 3 = 3 ohms. You would need a 3-ohm resistor to safely connect a 3-volt LED to a 220-volt source.
The current in a 220 volt circuit depends on the resistance of the load connected to it. Ohm's Law (I = V/R) states that current (I) is equal to voltage (V) divided by resistance (R). So, the current will vary based on the resistance of the circuit.
3 volt bulb gives the biggest resistance
resistance = volt / current . 440 volt across a parallel circuit means the same 440 volt across both resistance s. hence resistance r = volt / current . 440 / 20 amp = 27.5 ohms total resistance
The value of internal resistance of 1.5 volt battery is 0.5 ohms.
The current output is governed by the load resistance of the circuit. The battery will try and supply as much current as needed up until the battery goes dead.
It depends on the resistance of the circuit, as V=IR, so I=V/R (V=Voltage, I=Current, R=Resistance)
Just use Ohms Law: V=IR, that is, voltage (in Volt) = current (in Ampere) x resistance (in Ohms).
5 megohms
one volt applied across one ohm of resistance causes a current flow of one
Milli volt is one thousandth of a Volt and Milli amp is one thousandth of an Amp. Volt and Amp measure two different things and are not really comparable. Over simplified, here is how it works. Volt measures the 'pressure' that causes current to flow. Current flow is measured in Amps and depends on the how much resistance the 'pressure' has to overcome. Higher the resistance, lesser the current (Amp) for same pressure (Volt)
A: Decreasing the current and/or the resistance
Usually a volt meter is placed across a component to measure the voltage drop across that component. Doing this places the volt meter resistance in parallel with that component's resistance, which will always lower the total resistance. Since the volt meter resistance is usually very large relative to the resistance of the element being measured, the total resistance does not change significantly. The formula for total resistance of two parallel elements is: Rtot = (R1*R2)/(R1+R2), as R1 (the volt meter) >> R2, Rtot ~= (R1*R2) / (R1) = R2 If a volt meter is placed into a circuit instead of around an element of that circuit, it will raise the resistance of the circuit, load the circuit with, and interrupt "normal" operation of the circuit (normal operation = how things would be without the meter in place). More importantly, the volt meter would then be measuring the voltage developped across itself (instead of an element of the circuit), which is not the point of this tool / this would be a misapplication of a volt meter.
Use a properly rated potentiometer.