The larger the orbit, the longer the period of revolution. The Space Shuttle, when it is in orbit, revolves once around the earth in about 90 minutes. The moon ... and any other satellite at a distance of about a quarter million miles from earth ... takes about 27 days to revolve once around the earth.
The orbital speed would be approximately 7.63 km/s and the period would be approximately 95.59 minutes for a satellite orbiting Earth at an altitude of 1.44 x 10^3 m. These values can be calculated using the formula for orbital speed (v = √(GM/r)) and the formula for orbital period (T = 2π√(r^3/GM)), where G is the gravitational constant, M is the mass of Earth, and r is the altitude of the satellite above Earth's surface.
The mean radius of the asteroid Vesta is about 262.7 kilometers (163.2 miles).
The satellite is being pulled by the earths gravity all of the time, but the satellite also has an orbital velocity, meaning that is is travelling at high speed. These two opposing forces balance out, the 'sideways' speed of the satellite wants to take it away into space, but the gravity of the earth is always pulling it in. The satellite maintains its speed as there there are no frictional forces to slow it down in space, so it maintains an orbit.
Orbital velocity refers to the speed at which a planet travels in its orbit.
If the satellite appears to remain motionless over one spot on the earth, then I don'tneed to know the radius or anything else about orbital mechanics to calculate its period.It had better be equal to the earth's rotation period of 23hours 56minutes and about 4 seconds.
Orbital speed of a satellite: v - orbital speed G - gravitational consatnt R - radius of earth h - height of orbit
The formula to find the orbital speed v for a satellite in a circular orbit of radius r is v (G M / r), where G is the gravitational constant, M is the mass of the central body, and r is the radius of the orbit.
This question cannot be answered because:the total energy of the satellite includes its kinetic energy and that depends on its orbital speed. This is not specified;it is not clear what you mean by "potational": is it a typo for rotational or potential?what is R? The radius of the earth or the height of the satellite or some other measure?
The speed of the satellite is dependant on its distance from the surface of the planet. the greater the altitude, the greater the speed, or velocity. I would think that Velocity Equation would be a simple linear equation of the form; y=kx, where k is a constant. What that constant is for Mars, I do not know as I did not do Astronomy at Uni, only Physics subjects.
It has to be carried there by a rocket, which takes it to the required altitude and orbital speed.
Scientists must carefully set the right orbital speed for a satellite that will be orbiting Earth, so that it will orbit correctly. The wrong speed will have the satellite move too fast, or too slow, skewing information and possibly causing the satellite to fall out of orbit and back to the planet's surface.
The tangential velocity of an Earth satellite is its velocity perpendicular to the radius vector pointing towards the center of the Earth. It represents the speed at which the satellite is moving along its orbital path. This velocity is crucial for maintaining the satellite's orbit and is calculated using the satellite's distance from the center of the Earth and gravitational force acting upon it.
The speed of the satellite will remain the same regardless of doubling the mass, as long as the radius of its orbit remains constant. The speed of the satellite in orbit is determined by the gravitational force between the satellite and the celestial body it is orbiting, not the mass of the satellite itself.
When it is closest to the planet.One of the components of the acceleration, the normal acceleration, is equal to v2/r, where v is the satellite's speed and r is the radius of the current orbit followed by the satellite. So, the smaller the radius, the higher the acceleration.
The speed is variable; faster while closer to the Earth, and slower further away. But the actual speed varies by the orbital distance.
The orbital speed would be approximately 7.63 km/s and the period would be approximately 95.59 minutes for a satellite orbiting Earth at an altitude of 1.44 x 10^3 m. These values can be calculated using the formula for orbital speed (v = √(GM/r)) and the formula for orbital period (T = 2π√(r^3/GM)), where G is the gravitational constant, M is the mass of Earth, and r is the altitude of the satellite above Earth's surface.
This actually depends on the orbital radius, or distance from Earth's surface (or center). The further away the satellite is, the slower it travels to stay in orbit (related to Kepler's second law). A satellite that is really close to the atmosphere and barely in space needs to travel at about 7800m/s. A satellite can speed up and increase its tangential velocity to make its orbit bigger. A bigger orbit results in a lower speed. Interestingly, this means that an orbiter speeds up to slow down. Likewise, a satellite in a high orbit can fire its engines backwards to reduce its speed to get into a smaller, faster orbit, ultimately speeding up. ================================ In an orbit that's not a perfect circle, the speed in orbit is always changing. The satellite moves faster when it's closer to the Earth, and slower when it's farther out.