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Compression ratio (CR) is the total volume of a cylinder at BDC (bottom dead center) divided by total volume of space at TDC (top dead center).
To increase CR, you must either increase the total volume of displacement, or decrease the volume at TDC. This can be achieved by shaving the heads, increasing the bore, or increasing the stroke.
Provided there is room for valve clearance, shaving the heads is the simplest method.
What else can I help you with?
Is the energy of carnot engine is maximum?
The Carnot engine is the most efficient heat engine possible, but it does not produce maximum energy. It operates between two temperature reservoirs and has an upper limit on efficiency based on those temperatures. The efficiency of a Carnot engine is determined by the difference in temperature between the hot and cold reservoirs.
Is it possible to attain an efficiency of 100 percent in heat engines?
The maximum efficiency of the carnot engine only depends on two factors: 1 - The temperature of the hot reservoir (TH) 2 - The temperature of the cold reservoir (TC) And is given by (TH - TC) / TH « or » 1 - TC / TH So by that we can see the maximum efficiency (100%) would be when the difference of temperatures between the two reservoirs is infinite.
How would you increase the efficiency of a Carnot engine by increasing T1 or by decreasing T2 - why?
Increasing the temperature of the hot reservoir will increase efficiency. So will decreasing the temperature of the cold reservoir (heat sink). There are limits as to how cold you can get the heat sink however. Cutting the temperature of the heat sink in half will give the same improvement in efficiency as doubling the temperature of the heat source - but it's a lot harder to cut the temperature of the heat sink in half than to double the temperature of the heat source. Also, the heat sink is usually around the temperature of the environment - which you have little control over. ... bottom line - you are probably going to find it easier to improve the efficiency by raising T1 than by decreasing T2.
What is a Chevy 305 engine bored 040 over called?
A Chevy 305 engine bored .040 over would typically be referred to as having a +.040 bore, indicating the increase in bore diameter from the standard size. This modification can increase the engine's displacement and potentially enhance its performance.
How many watts is a block heather?
A typical block heater for a car engine would be around 400-1500 watts, depending on the size and efficiency of the heater. This kind of heater is used to keep the engine warm in cold weather for easier start-ups.
Is the energy of carnot engine is maximum?
The Carnot engine is the most efficient heat engine possible, but it does not produce maximum energy. It operates between two temperature reservoirs and has an upper limit on efficiency based on those temperatures. The efficiency of a Carnot engine is determined by the difference in temperature between the hot and cold reservoirs.
What temperature would the cold reservoir need to be for a Carnot engine to achieve 100 percent efficiency?
For a Carnot engine to achieve 100 percent efficiency, the temperature of the cold reservoir would need to be absolute zero (0 Kelvin). This is because the efficiency of a Carnot engine is given by 1 - (Tc/Th), where Tc is the temperature of the cold reservoir and Th is the temperature of the hot reservoir, and efficiency is maximized as Tc approaches absolute zero.
What happens to the efficiency of a heat engine when the temperature of the reservoir into which heat energy is rejected is lower?
The efficiency of a heat engine increases when the temperature of the reservoir into which heat energy is rejected is lower. This is because a lower temperature of the sink allows for a greater temperature difference between the hot and cold reservoirs, which leads to a higher efficiency according to the Carnot efficiency formula.
What is a carnot's engine?
a Carnot cycle is a perfect cycle of energy conversion from heat to mechanical energy and back without loss. This is an impossibility due to losses inherent in any energy transfer. A Carnot engine would theoretically use all available energy for each energy transfer.
What is the ideal efficiency of an automobile engine where fuel is heated to 2900 K and the outdoor air is at 285 K?
The ideal efficiency of a Carnot engine can be calculated using the formula: Efficiency = 1 - (T_cold / T_hot), where T_cold is the temperature of the cold reservoir (in this case, 285 K) and T_hot is the temperature of the hot reservoir (2900 K). Plugging in the values, the ideal efficiency would be 1 - (285/2900) = 0.902 or 90.2%.
Why would Engine temperature increase at idling?
Because the efficiency of the fan and the water pump degrades at low RPM.
Is it possible that in an engine there will be an 100 percent efficiency without the presence of friction and other irreversibility?
No. No engine can be 100% efficient. The Carnot cycle is mathematically proven to provide an upper bound for efficiency. The efficiency of the Carnot cycle can be calculated from the formula:eta = 1 - Tc/THwhereis eta is efficiencyTc is the temperature of the heat sinkTH is the temperature of the heat source.The only way to make the (theoretical) efficiency 100% would be to have a heat sink at absolute zero (which is impossible due to the 2nd law of thermodynamics) or to have the heat source at a temperature of infinity (which is impossible due to the 1st law). Real engines always operate at an efficiency less than the theoretical because they operate on a less efficient cycle and/or posses real irreversibility in their operation. Consequently no engine - real or theoretical - can operate at 100% efficiency.
What is the ideal efficiency of a heat engine that operates with its hot reservior at 500k and its sink at 300k?
The ideal efficiency of a heat engine operating between a hot reservoir at 500 K and a cold reservoir at 300 K is given by the Carnot efficiency formula: Eff = 1 - (Tc/Th) where Tc is the temperature of the cold reservoir (300 K) and Th is the temperature of the hot reservoir (500 K). Plugging in the values, the efficiency would be Eff = 1 - (300/500) = 1 - 0.6 = 0.4 or 40%.
Does an ideal machine would have an efficiency greater than one?
No, an efficiency greater than one would not be possible, since that would violate a very fundamental law of physics: conservation of energy. The efficiency of an "ideal machine" would be one, in many cases; the efficiency of an ideal Carnot engine would be less than one.
What is carnots engine?
a Carnot cycle is a perfect cycle of energy conversion from heat to mechanical energy and back without loss. This is an impossibility due to losses inherent in any energy transfer. A Carnot engine would theoretically use all available energy for each energy transfer.
Is it possible to attain an efficiency of 100 percent in heat engines.explain?
A heat engine operating between 2 temperatures, Thot, the heat source, and Tcold, the heat sink, can be 100% efficient only when Tcold is absolute zero. Carnot worked out the equation to determine the best possible efficiency of a heat engine designed to produce mechanical energy ("Work") from heat energy: Wout = (Heat Energy in at Thot) x (Thot - Tcold)/(Thot) Note that (Thot - Tcold)/(Thot) is 1 only if Tcold is zero. In every other case, the ratio is less than 1. The amount of heat energy discharged to the heat sink at Tcold is: (Heat Energy in at Thot) - Wout. (You can work this out from the equation. It reflects the law of conservation of energy. ) This just means that all the heat energy absorbed by the heat engine is converted into either mechanical energy or heat energy at a lower temperature. No energy is lost and no extra energy is created. "Efficiency" according to Carnot's equation tells us the best possible ratio between these two energy outputs that nature allows a heat engine to achieve. You can think of a heat engine as a device that splits an amount of heat energy at some high temperature into mechanical energy and heat energy at some lower temperature. Kind Regards, Colin Dunstan Author: "cyclic heat to work conversion systems"
Is it possible to attain an efficiency of 100 percent in heat engines?
The maximum efficiency of the carnot engine only depends on two factors: 1 - The temperature of the hot reservoir (TH) 2 - The temperature of the cold reservoir (TC) And is given by (TH - TC) / TH « or » 1 - TC / TH So by that we can see the maximum efficiency (100%) would be when the difference of temperatures between the two reservoirs is infinite.
