Using Carnot's equation of ideal efficiency, N= 1-C/H C is the temperature of the cold reservoir and H is the temperature of the hot reservoir.
So it would be N= 1-300/500= .4 or 40%
The ideal efficiency of a Carnot engine can be calculated using the formula: Efficiency = 1 - (T_cold / T_hot), where T_cold is the temperature of the cold reservoir (in this case, 285 K) and T_hot is the temperature of the hot reservoir (2900 K). Plugging in the values, the ideal efficiency would be 1 - (285/2900) = 0.902 or 90.2%.
An ideal machine operates without any energy losses, friction, or other inefficiencies, providing 100% efficiency at all times. In contrast, an actual machine experiences energy losses due to factors such as friction, heat, and inefficiencies in its components, resulting in less than 100% efficiency in its operation.
No, an efficiency greater than one would not be possible, since that would violate a very fundamental law of physics: conservation of energy. The efficiency of an "ideal machine" would be one, in many cases; the efficiency of an ideal Carnot engine would be less than one.
An ideal machine is one that operates with 100% efficiency, meaning that all input energy is converted into useful work output without any energy loss. An example could be a hypothetical machine that requires no external energy input to perform its tasks. However, in reality, achieving 100% efficiency is not possible due to factors such as friction and heat loss.
The Carnot's heat engine is an ideal heat engine.In this process the source has infinite thermal heat capacity and the temperature of the source is constant( when we take large amount of heat from the source but it has same temperature ) .This is one assumption. The sink is also this condition means if it gain maximum heat energy from the source the temperature of the sink is also constant . this is another assumption. Ideal gas works as working substance(system).enclose in a cylinder whose walls and piston are perfectly adiabatic and base is perfectly diathermic.conversion of heat to work is an irriversible process but in carnot's heat engine it is possible.the initial temparature of system is infinite it is depend on temparature of the system.the perfect ideal gas and the perfect insulators are not exist so this process is only assumption.there is no heat engine which has more efficiency than the carnot's heat engineRGUKT IIIT NUZVID: N091528http://wiki.answers.com/'Why_is_the_carnot_efficency_the_maximum_efficiency_for_a_heat_engine&action=edit
friction, imperfect insulation
The ideal efficiency of a Carnot engine can be calculated using the formula: Efficiency = 1 - (T_cold / T_hot), where T_cold is the temperature of the cold reservoir (in this case, 285 K) and T_hot is the temperature of the hot reservoir (2900 K). Plugging in the values, the ideal efficiency would be 1 - (285/2900) = 0.902 or 90.2%.
The ideal efficiency of an engine operating between two thermal reservoirs is determined by the Carnot efficiency formula: ( \eta = 1 - \frac{T_{cold}}{T_{hot}} ). If both the hot reservoir and the exhaust are at 400 K, then the temperature of the cold reservoir is also 400 K. This results in ( \eta = 1 - \frac{400}{400} = 0 ). Therefore, the ideal efficiency of the engine in this scenario is 0%, meaning no work can be extracted.
The answer is 38.
An ideal machine operates without any energy losses, friction, or other inefficiencies, providing 100% efficiency at all times. In contrast, an actual machine experiences energy losses due to factors such as friction, heat, and inefficiencies in its components, resulting in less than 100% efficiency in its operation.
No, an efficiency greater than one would not be possible, since that would violate a very fundamental law of physics: conservation of energy. The efficiency of an "ideal machine" would be one, in many cases; the efficiency of an ideal Carnot engine would be less than one.
The normal operating temperature of a 409 engine typically ranges between 190°F to 220°F (88°C to 104°C). Maintaining this temperature is crucial for optimal performance and efficiency. If the engine consistently runs outside this range, it may indicate issues such as cooling system problems or improper tuning. Regular monitoring can help ensure the engine operates within its ideal temperature range.
It is efficiency of the propelling device in converting the applied torque into useful thrust. In an IDEAL propeller the freestream velocity and the slipstream velocity should be same. The higher the exhaust/slip stream velocity, higher is the wasted kinetic energy. Thus turbojet engine has lower propulsive efficiency and turbo-prop engine has higher propulsive efficiency.
An ideal machine is one that operates with 100% efficiency, meaning that all input energy is converted into useful work output without any energy loss. An example could be a hypothetical machine that requires no external energy input to perform its tasks. However, in reality, achieving 100% efficiency is not possible due to factors such as friction and heat loss.
In an ideal frictionless system, the work input equals the output and force. Your Welcome!!!
In an ideal frictionless system, the work input equals the output and force. Your Welcome!!!
Yes. Without it, the engine management system can no longer control the engine for ideal fuel and pollution efficiency. It'll burn more and dirtier. And this can damage the catalytic converter.