27.59
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
2 moles of Ca and 4 moles of OH
CaOH2 is a base because calcium is compounded with hydroxide, rather than hydrogen. Most if not all acids' names begin with 'H', while most if not all bases' names end with 'OH'.
To find the mass of Ca(OH)₂ in 500 mL of a 0.00500 M solution, first calculate the number of moles of Ca(OH)₂: [ \text{Moles} = \text{Molarity} \times \text{Volume (in L)} = 0.00500 , \text{mol/L} \times 0.500 , \text{L} = 0.00250 , \text{mol} ] Next, calculate the mass using the molar mass of Ca(OH)₂ (approximately 74.09 g/mol): [ \text{Mass} = \text{Moles} \times \text{Molar Mass} = 0.00250 , \text{mol} \times 74.09 , \text{g/mol} \approx 0.1852 , \text{g} ] Thus, there are approximately 0.185 grams of Ca(OH)₂ in 500 mL of a 0.00500 M solution.
The reaction between calcium oxide (CaO) and water (H2O) to form calcium hydroxide (Ca(OH)2) is a synthesis reaction. In this type of reaction, two or more reactants combine to form a single product. The equation can be represented as: CaO + H2O → Ca(OH)2. This reaction is also classified as a hydration reaction, as water is added to a solid compound.
http://wiki.answers.com/Q/Calculate_for_a_solution_formed_by_adding_4.80ml_of_0.130_M_KOH_to_19.0ml_of_7.6x102_M_of_CaOH2"
Nope... it is not.
Calcium hydroxide.
Calcium hydroxide.
Laboratory preparation of ammonia or NH3 requires using ammonium chloride and calcium hydroxide. The reaction equation is 2NH4Cl plus CaOH2 gives the products 2NH3 plus CaCl2 plus 2H2O. The ammonium chloride and calcium hydroxide are heated for this reaction.
CaCl2 and H2O
In one mole of this solution, there are seven moles of H2O.
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
2 moles of Ca and 4 moles of OH
Ca(OH)2 and Na2O
Calcium Hydroxide, or CaOH2, is a base. Generally compounds containing hydroxyl groups and metals will act as bases in reaction.
The molecular weight of Ca(OH)2 (calcium hydroxide) is approximately 74.09 g/mol.