Haemophilia is a recessive, X-based disorder. The woman in your question is a carrier, meaning she has the defective gene, but isn't bothered by it. Therefor, the woman is of the type 'Xx'. The man is of the type 'XY', not carrying the defective gene. Their children can then be: XX, xX, XY, xY. This means that their daughters won't be affected by it, but might carry it, and their sons either not carry it at all, or carry it and be haemophilic.
Genotypes are not created by phenotypes, they are the alleles/genes of the organism. Genotypes (in combination with environment) produce phenotypes. It would be expected that the genotypes Bb and BB would produce the phenotype B.
No, there are more than two possible genotypes among the offspring when both parent genotypes are Aa. The potential genotypes for the offspring are AA, Aa, and aa, resulting in a total of three different genotypes. The expected ratio from a Punnett square for this cross is 1 AA : 2 Aa : 1 aa.
With a dihybrid cross, there are 9 possible genotypes and 4 possible phenotypes. The ratio of phenotypes expected is 9 LR : 3 Lr : 3 lR : 1 lr. The probability of a homozygous dominant for both traits is 1/16 or 6%. The probability of having a dominant phenotype for both traits is 9/16 or 56%. 9/16 is roughly equal to 3/5 - so this is the expected ratio.
A ratio of phenotypes produced by a cross is a description of the expected proportion of different physical traits or characteristics that offspring will inherit from their parents. This ratio is determined by the combination of genes passed down from each parent, and can be predicted using Punnett squares or other genetic tools.
To provide an accurate answer, I would need the specific parental genotypes involved in the cross. However, if we assume a simple Mendelian cross between two heterozygous parents (e.g., Aa x Aa), the expected genotypes of the offspring would be: AA, Aa, Aa, and aa. This would yield 1 AA, 2 Aa, and 1 aa, resulting in a total of four offspring with the genotypic ratio of 1:2:1.
Genotypes are not created by phenotypes, they are the alleles/genes of the organism. Genotypes (in combination with environment) produce phenotypes. It would be expected that the genotypes Bb and BB would produce the phenotype B.
Punnett Squares do not directly tell you the percentages of phenotypes and genotypes, it tells you the probability of the expected genotypes. Based on the Punnett Square, you can infer about the genotypic and phenotypic ratios.
The possible genotypes and phenotypes of the offspring can be determined using a Punnett square, a grid that shows the possible combinations of alleles that can result at fertilisation. The Punnett square below shows the expected genotypes of the offspring of parent pea plants that both have the genotype Rr.
If the expected genotypes match the observed genotypes perfectly, there should be no disagreement. If there is disagreement, it can be quantified using a statistical measure such as the chi-squared test to determine the degree of deviation between the expected and observed genotypes. The larger the difference between the expected and observed genotypes, the greater the disagreement.
Mendel Diagrams. If the offspring gets a dominate gene from both parents, the offspring will exhibit traits from the dominate gene. If the offspring gets a dominate gene from one parent and a recessive gene from another, the offspring will exhibit traits from the dominate gene. If the offspring get a recessive gene from both parents, the offspring will exhibit traits from the recessive gene.
To determine the fraction of children that should be homozygous smooth, we need to know the genetic information regarding the traits involved, specifically the alleles for smooth and rough phenotypes. If we assume that smooth is a dominant trait (S) and rough is recessive (s), we can use a Punnett square based on the parental genotypes. Without specific parental genotypes provided, it’s impossible to calculate the exact fraction; however, if both parents are heterozygous (Ss), then 1/4 of the offspring would be expected to be homozygous smooth (SS).
pleiotropy
No, there are more than two possible genotypes among the offspring when both parent genotypes are Aa. The potential genotypes for the offspring are AA, Aa, and aa, resulting in a total of three different genotypes. The expected ratio from a Punnett square for this cross is 1 AA : 2 Aa : 1 aa.
In a dihybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively. In a monohybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively.
The expected results are half Cc and half cc.
anythimg longer than the expected value reference range, which is 25-39secs
A phenotype is a physical characteristic. For a human an observed phenotype example would be hair colour (e.g brown) or eye colour (green). An observed phenotype is a physical characteristic that can be seen directly or indirectly (internal organs) caused by an individual's genotype.