Yes
yes
At 25°C, the solubility concentration of sulfate ions (SO₄²⁻) in a saturated solution typically depends on the specific sulfate salt being considered. For example, in the case of barium sulfate (BaSO₄), its solubility product constant (Ksp) indicates that the concentration of sulfate ions in a saturated solution is approximately 0.0001 M. However, for other sulfate salts, such as sodium sulfate (Na₂SO₄), the solubility can be significantly higher. Therefore, the solubility concentration of sulfate ions varies by the specific compound being dissolved.
25 degrees Celsius = 77 degrees Fahrenheit
h+ = 3.4 x 10-4 ph= 4.5 oh- = 2.5x10-9
Nineteen degrees Celsius is a measure of temperature. It falls between the freezing point of water (0 degrees Celsius) and room temperature (around 20-25 degrees Celsius).
No. If a saturated solution is heated, it will no longer be fully saturated. Water at 25°C will be saturated with sugar at a ratio of 100 grams of sugar to 100 grams of water. At 50°C it would take 130 grams of sugar to reach saturation. See this link for a full explanation: http://www.scienceclarified.com/Ro-Sp/Solution.html
20 to 25 degrees Celsius is equivalent to 68 to 77 degrees Fahrenheit respectively.
the solubility of urea solution at 20 degrees celsius is 107.9 g / 100 ml
Solution: 20+25=? 20x.2=4 20+4=24 ans.
add 25ml more of solution x * 20 = 100 * 25 x = 25
It is about 20 to 25 grams of saturated fat out of a recommended total intake of about 70 grams of fat (about 30% saturated and 70% unsaturated).
The principal solution for sin(A + 5) = cos(3A - 25), with angles measured in degrees, is A = 15 degrees.
-25 is colder than -20. On the temperature scale, lower numbers indicate colder temperatures. Therefore, -25 degrees is a lower temperature than -20 degrees.
The concentration of a saturated solution of copper sulfate is approximately 25% by weight, which means that 25 grams of copper sulfate are dissolved in 100 grams of water at a specific temperature. At room temperature, this solution is around 47-50 grams of copper sulfate per 100 milliliters of water.
The answer is 20+25=45
This is a solution of 10 g KCl/100 g water.
yes