The answer is six.
When Tt plants (heterozygous for a trait) are pollinated, they can produce offspring with the genotypes TT, Tt, and tt. This follows the principles of Mendelian genetics, where the expected phenotypic ratio among the offspring would be 3:1 for dominant to recessive traits. Therefore, about 75% of the offspring will exhibit the dominant trait, while 25% will display the recessive trait.
The expected phenotypic ratio for their offspring is 1:1, with a 50% chance of being color blind (male with the X-linked recessive trait) and a 50% chance of having normal color vision. This is because the daughter is a carrier of the recessive allele, which can be passed on to her offspring regardless of the father's color vision status.
Expected based on probability.
There is a 25% chance (1 in 4) that the offspring will be homozygous for the trait. This is because when both parents are heterozygous (Aa), they can pass on either the dominant allele (A) or the recessive allele (a) to their offspring, resulting in a 1 in 4 chance of the offspring receiving the recessive allele from both parents and becoming homozygous (aa) for that trait.
This would be because phenotypes are the observable characteristics whilst genotypes are the actual genes. If we are given the genes: R (dominant) and r (recessive), and 2 organisms with Rr genes (one dominant and one recessive) produce offspring, their offspring will have one of the following genes, with the percentage chance in brackets: RR (25%) Rr (50%) rr (25%) However, you can't detect recessive genes if a dominant gene is present, thus there will be no observable difference between the RR and Rr organism, besides for their offspring. Thus, the phenotype is 75% and 25%, unlike for the genotype.
Half of the offspring, or 100 rabbits, would be expected to be white when offspring from a heterozygous brown rabbit and a white rabbit are produced. This is due to the dominant-recessive inheritance pattern where brown is dominant and white is recessive.
1000
Let T=trait (dominant) Let t= trait (recessive) Father has Tt and mother also has Tt The possible combinations for offspring are: TT Tt Tt and tt Therefore There is a 3/4 change of the offspring having the dominant trait and a 1/4 Chance of the offspring having the recessive trait It should also be noted that there is a 1/4 chance of the offspring carrying two dominant genes meaning that any of their children will also share the dominant trait
When Tt plants (heterozygous for a trait) are pollinated, they can produce offspring with the genotypes TT, Tt, and tt. This follows the principles of Mendelian genetics, where the expected phenotypic ratio among the offspring would be 3:1 for dominant to recessive traits. Therefore, about 75% of the offspring will exhibit the dominant trait, while 25% will display the recessive trait.
Fyugugy
25%
The expected phenotypic ratio for their offspring is 1:1, with a 50% chance of being color blind (male with the X-linked recessive trait) and a 50% chance of having normal color vision. This is because the daughter is a carrier of the recessive allele, which can be passed on to her offspring regardless of the father's color vision status.
Mendel Diagrams. If the offspring gets a dominate gene from both parents, the offspring will exhibit traits from the dominate gene. If the offspring gets a dominate gene from one parent and a recessive gene from another, the offspring will exhibit traits from the dominate gene. If the offspring get a recessive gene from both parents, the offspring will exhibit traits from the recessive gene.
The expected phenotype ratio of seed color in the offspring of an F1 x F1 cross is 3:1. This is because the F1 generation is heterozygous for the trait, resulting in a 3:1 ratio of dominant to recessive phenotypes in the offspring.
To determine the hair color of the guinea pigs' offspring, we need to know the genotypes of the parents. If one parent is homozygous dominant (BB) and the other is homozygous recessive (bb), all offspring will be heterozygous (Bb) and will have black hair. If both parents are heterozygous (Bb), approximately 25% of the offspring are expected to be homozygous dominant (BB), 50% heterozygous (Bb), and 25% homozygous recessive (bb), resulting in a 75% chance of black hair and a 25% chance of white hair.
Expected based on probability.
There is a 25% chance (1 in 4) that the offspring will be homozygous for the trait. This is because when both parents are heterozygous (Aa), they can pass on either the dominant allele (A) or the recessive allele (a) to their offspring, resulting in a 1 in 4 chance of the offspring receiving the recessive allele from both parents and becoming homozygous (aa) for that trait.