Yes, the equation 2Na + 4Cl → 2NaCl is balanced. On the left side, there are 2 sodium (Na) atoms and 4 chlorine (Cl) atoms, which matches the right side where there are also 2 sodium atoms and 2 molecules of NaCl, totaling 4 chlorine atoms. Thus, both sides of the equation have the same number of each type of atom.
The balanced equation for the reaction between sodium (Na) and chlorine (Cl2) to form sodium chloride (NaCl) is 2Na + Cl2 -> 2NaCl. This equation is balanced because it has an equal number of each type of atom on both sides of the reaction arrow.
See that 3 subscript on O in NaClO3 ? Hint to double the moles there. 2NaClO3 -> 2NaCl +3O2
The balanced equation is: C5H12 + 8O2 → 5CO2 + 6H2O. Therefore, the coefficient for oxygen in the balanced equation is 8.
CuCl2 + Na2SO4 --> CuSO4 + 2NaCl
No, the equation is not balanced. The correct balanced equation would be: 2Na + F2 -> 2NaF
The balanced equation for CaSO4 + 2NaCl is CaCl2 + Na2SO4.
The balanced equation for the reaction between sodium (Na) and chlorine (Cl2) to form sodium chloride (NaCl) is 2Na + Cl2 -> 2NaCl. This equation is balanced because it has an equal number of each type of atom on both sides of the reaction arrow.
HCl + NaOH = H2O + NaCl is already balanced.
The balanced equation is 2HCl + Na2S → H2S + 2NaCl. This is balanced as the number of atoms of each element is the same on both sides of the equation.
This equation does not balance because 2 chlorine salts do not react with eachother. However, they are both highly soluable in water. By adding H2O, this equation can be balanced.
2Na (s) + 2HCl (aq) -> 2NaCl (aq) + H2 (g)
I think this is right... Cl2 + 2NaBr = 2NaCl + Br2
The balanced chemical equation for the reaction between Na2SO3 (sodium sulfite) and HCl (hydrochloric acid) is: Na2SO3 + 2HCl -> 2NaCl + H2O + SO2
The answer is TWO (2)Na2CO3 + CaCl2 --> 2 NaCl + CaCO3
The equation given is correctly balanced, because it contains the same numbers of each kind of atoms in the reactants as in the products.
No, it should be:2 Na(s) + 2HCl(g) --> H2(g) + 2 NaCl(s)By the way: sodium at normal conditions is a solid metal (s), not gaseous (g)
2NaBr (s) + Cl2 (g) --------> 2NaCl (s) + Br2 (g)