It is a salt in the sense that it is an ionic compound. Al forms the positively charged ion (cation) Al3+ and chlorine forms the negatively charge ionc (anion) Cl-. However, AlCl itself is not a salt because it is not a legit formula. With a 3+ charge on the aluminum and only a -1 charge on the chloride, you need three Cl-'s to balance the Al3+. So the actual salt is AlCl3.
Mg+AlCl=MgCl+Al Magnesium+Aluminium chloride=Magnesium chloride+ Aluminium This happens because magnesium is a more reactive element then aluminum so chlorine swaps places and forms a new compound with magnesium.
The dissociation equation for aluminum chloride (AlCl₃) in water is as follows: [ \text{AlCl}_3 (s) \rightarrow \text{Al}^{3+} (aq) + 3 \text{Cl}^- (aq) ] When AlCl₃ dissolves in water, it separates into aluminum ions (Al³⁺) and chloride ions (Cl⁻), resulting in an aqueous solution.
In one mole of aluminum chloride (AlCl₃), there are three moles of chlorine atoms. This is because each formula unit of AlCl₃ contains three chlorine (Cl) atoms. Therefore, in one mole of AlCl₃, there are 3 moles × 6.022 × 10²³ (Avogadro's number) = 1.8066 × 10²⁴ chlorine atoms.
That's not a valid empirical formula. Assuming you meant aluminum chloride and just didn't know the real formula, it's AlCl3 with four atoms per formula unit.
The compound AlCl₃, also known as aluminum chloride, contains two different elements: aluminum (Al) and chlorine (Cl). Specifically, there is one aluminum atom and three chlorine atoms in each formula unit of AlCl₃. Therefore, there are a total of two distinct elements in the compound.
No such chemical as 'AlCl';. However, if you means 'AlCl3'. (Aluminium chloiride) , then it is a chemical salt
AlCl would be aluminum chloride, though the actual formula is AlCl3
AlCl refers to aluminum chloride, a chemical compound composed of aluminum and chlorine atoms. It is commonly used in various industrial processes, such as in the production of polymers and pharmaceuticals.
Mg+AlCl=MgCl+Al Magnesium+Aluminium chloride=Magnesium chloride+ Aluminium This happens because magnesium is a more reactive element then aluminum so chlorine swaps places and forms a new compound with magnesium.
Using the balanced equation 2 AlCl₃ + 3 Pb(NO₃)₂ → 3 PbCl₂ + 2 Al(NO₃)₃, the mole ratio between AlCl₃ and PbCl₂ is 2:3. Therefore, if 14 moles of AlCl₃ are consumed, 9.33 moles (14 moles / 2 * 3) of PbCl₂ will be produced.
Displacement reaction
That's not a valid empirical formula. Assuming you meant aluminum chloride and just didn't know the real formula, it's AlCl3 with four atoms per formula unit.
The reaction between aluminum iodide (AlI₃) and chlorine gas (Cl₂) typically produces aluminum chloride (AlCl₃) and iodine (I₂). The balanced chemical equation for this reaction is: 2 AlI₃ + 3 Cl₂ → 2 AlCl₃ + 3 I₂. Therefore, the products of this reaction are aluminum chloride and iodine.
When aluminum metal reacts with hydrochloric acid, it forms aluminum chloride and hydrogen gas. The reaction is as follows: 2 Al (s) + 6 HCl (aq) → 2 AlCl₃ (aq) + 3 H₂ (g). The aluminum chloride formed is a salt that remains dissolved in the solution.
The chemical name for AlCl is aluminum chloride. It is a chemical compound made up of aluminum and chlorine atoms in a 1:1 ratio. Aluminum chloride is commonly used in industrial processes and as a catalyst in organic reactions.
The balanced chemical equation for the reaction of aluminum with hydrochloric acid (HCl) to form hydrogen gas (H2) and aluminum chloride (AlCl3) is: 2 Al + 6 HCl → 2 AlCl3 + 3 H2
The balanced chemical equation for the reaction is: 2Al + 3Cl₂ → 2AlCl₃ Calculate the limiting reactant: Moles of Al: 35.5g / molar mass of Al Moles of Cl₂: 39.0g / molar mass of Cl₂ Determine which reactant gives the lower amount of AlCl₃ produced. Once you know the limiting reactant, use stoichiometry to calculate the grams of AlCl₃ produced.