Colorless Solid
1.39 moles
AlF3 (aluminum fluoride) is a polar molecule due to the difference in electronegativity between aluminum and fluorine atoms. The polar covalent bonds in AlF3 result in an uneven distribution of electrons, leading to a net dipole moment.
The fullest correct name is monoaluminum trifluoride. It is often called more simply aluminum trifluoride, or even aluminum fluoride.
molar mass of AlF3 = 83.9767 g/molmolality = moles solute per kg solventmoles solute = 131 g x 1 mol/83.9767 g = 1.56 moleskg solvent = 3.60 kgMOLALITY = 1.56 moles/3.60 kg = 0.433 m (3 significant figures)
Aluminum fluoride (AlF3) is a compound formed by the reaction of aluminum and fluorine. It is commonly used as a catalyst in organic synthesis and as an additive in the production of aluminum metal.
The chemical formula of the compound formed between aluminum (Al) and fluorine (F) is AlF3, aluminum fluoride. It is a white solid that is commonly used in the production of aluminum and in various industrial applications.
Yes. Most metal to non-metal combinations are crystalline solids. The formula for aluminum fluoride is AlF3.
The chemical formula for aluminum fluoride is AlF3.
molar mass AlF3 = 83.98 g/mole33.4 g AlF3 x 1 mole/83.98 g = 0.398 molesEach mole of AlF3 contains 3 moles of F- anions, because AlF3 ==> Al^3+ + 3F^-.Thus, moles of anions = 3 x 0.398 = 1.19 moles of anions
The correct chemical formula for aluminum fluoride is AlF3.
The first symbol represnts the compound magnesium iodide (MgI2) and the second symbol represents aluminum fluoride (AlF3)
Fluorine reacts vigorously with aluminum to form aluminum fluoride (AlF3). This reaction is highly exothermic and can be explosive, as fluorine is a highly reactive element. Aluminum fluoride is a white solid that is commonly used in the production of aluminum metal.
No, AlF3 is not covalent. It is an ionic compound composed of aluminum cations (Al^3+) and fluoride anions (F^-).
The oxidation number of Al in AlF3 is +3 because fluorine has an oxidation number of -1 and there are three fluorine atoms in AlF3. This results in a neutral compound with an overall charge of 0.
aluminum fluorite
To find the number of moles of anions in 37.4 g of AlF3, we first need to calculate the molar mass of AlF3. Aluminum (Al) has a molar mass of 26.98 g/mol, and fluorine (F) has a molar mass of 19.00 g/mol. So, the molar mass of AlF3 is 26.98 + (3 * 19.00) = 83.98 g/mol. Therefore, the number of moles of AlF3 in 37.4 g is 37.4 g / 83.98 g/mol = 0.445 moles. Since there are 3 fluoride ions (anions) in each formula unit of AlF3, the number of moles of anions in 37.4 g of AlF3 is 0.445 moles * 3 = 1.34 moles.
Al(FlO3)3. Al has a charge of +3 and FlO3 has a charge of -1 so 3 fluorate ions are needed for every Al ion to balance the charge of the compound. ***extra--if you didn't know what fluorate was.... A well known ion, ClO3 (the chlorate ion), has a charge of -1. Fl is in the same group as Cl so the fluorate ion will have the same number of oxygens and the same charge as ClO3.