Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)
Colorless Solid
When you mix Pb2+ and OH-, they will react to form a precipitate of lead (II) hydroxide, which has the chemical formula Pb(OH)2. This is an insoluble compound that will form a solid or a cloudy solution.
1.39 moles
The spectator ions in this precipitation equation are K+ and NO3-. The non-spectator ions are Pb2+ and I-. They combine to form the precipitate PbI2.
void swap (int &pa, int &pb) { *pa ^= *pb; *pb ^= *pa; *pa ^= *pb; }
a peanut buter and jelly or jam sandwich
2 PbO + C -> 2 Pb + CO2
The chemical formula for aluminum fluoride is AlF3.
molar mass AlF3 = 83.98 g/mole33.4 g AlF3 x 1 mole/83.98 g = 0.398 molesEach mole of AlF3 contains 3 moles of F- anions, because AlF3 ==> Al^3+ + 3F^-.Thus, moles of anions = 3 x 0.398 = 1.19 moles of anions
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
The correct chemical formula for aluminum fluoride is AlF3.
NI(NO3)3+pbbr4nibr3+pb(no3)4
Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)
To balance the chemical equation Pb + PbO2 + H2SO4 → H2O + PbSO4, start by balancing the Pb atoms on the left side by adding a coefficient of 2 in front of Pb on the left side. Then balance the SO4 atoms by adding a coefficient of 4 in front of H2SO4. The balanced equation is 2Pb + PbO2 + 4H2SO4 → 2H2O + 2PbSO4.
The first symbol represnts the compound magnesium iodide (MgI2) and the second symbol represents aluminum fluoride (AlF3)
Pb which is neutral has 82 electrons. Thus, if it has a 4+ charge, then it has 78 electrons.