Pb (lead) and AlF3 (aluminum fluoride) can react under certain conditions, typically involving heat. Lead can displace aluminum from aluminum fluoride, forming lead fluoride (PbF2) and aluminum (Al). The reaction may proceed as follows: Pb + AlF3 → PbF2 + Al. However, this reaction is not commonly encountered in standard chemical practices.
Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)
Colorless Solid
When you mix Pb2+ and OH-, they will react to form a precipitate of lead (II) hydroxide, which has the chemical formula Pb(OH)2. This is an insoluble compound that will form a solid or a cloudy solution.
1.39 moles
The spectator ions in this precipitation equation are K+ and NO3-. The non-spectator ions are Pb2+ and I-. They combine to form the precipitate PbI2.
void swap (int &pa, int &pb) { *pa ^= *pb; *pb ^= *pa; *pa ^= *pb; }
a peanut buter and jelly or jam sandwich
2 PbO + C -> 2 Pb + CO2
The chemical formula for aluminum fluoride is AlF3.
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
molar mass AlF3 = 83.98 g/mole33.4 g AlF3 x 1 mole/83.98 g = 0.398 molesEach mole of AlF3 contains 3 moles of F- anions, because AlF3 ==> Al^3+ + 3F^-.Thus, moles of anions = 3 x 0.398 = 1.19 moles of anions
The correct chemical formula for aluminum fluoride is AlF3.
NI(NO3)3+pbbr4nibr3+pb(no3)4
Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)
To balance the chemical equation Pb + PbO2 + H2SO4 → H2O + PbSO4, start by balancing the Pb atoms on the left side by adding a coefficient of 2 in front of Pb on the left side. Then balance the SO4 atoms by adding a coefficient of 4 in front of H2SO4. The balanced equation is 2Pb + PbO2 + 4H2SO4 → 2H2O + 2PbSO4.
The first symbol represnts the compound magnesium iodide (MgI2) and the second symbol represents aluminum fluoride (AlF3)
Pb which is neutral has 82 electrons. Thus, if it has a 4+ charge, then it has 78 electrons.