You will get Pb(OH)4
The periodic symbol for lead is Pb.
Pb2+ is more stable than Pb4+ because the 6s and 6p orbitals in Pb have poor shielding ability, making it energetically unfavorable for Pb to lose 4 electrons and achieve the 4+ oxidation state. The higher charge of Pb4+ leads to greater electron-electron repulsions, making it less stable than Pb2+.
Pb3(PO)4 would be the correct answer but it isn't because this compound does NOT exsist: Pb3(PO4)4 or Pb3(PO3)4 are possible phosphate and phosphite salt of Pb(4+) ions.
The symbol for a lead ion is Pb, and the charge can vary depending on the specific ion. Common lead ions include Pb^2+ and Pb^4+.
The oxidation state of Pb in PbO2 is +4. In this compound, oxygen is generally assigned an oxidation state of -2 and since there are two oxygen atoms, the total oxidation state contributed by oxygen is -4. To balance the charge for the compound, the lead atom must have an oxidation state of +4.
a peanut buter and jelly or jam sandwich
NI(NO3)3+pbbr4nibr3+pb(no3)4
Pb which is neutral has 82 electrons. Thus, if it has a 4+ charge, then it has 78 electrons.
To balance the chemical equation Pb + PbO2 + H2SO4 → H2O + PbSO4, start by balancing the Pb atoms on the left side by adding a coefficient of 2 in front of Pb on the left side. Then balance the SO4 atoms by adding a coefficient of 4 in front of H2SO4. The balanced equation is 2Pb + PbO2 + 4H2SO4 → 2H2O + 2PbSO4.
Your formulas are not correct.
The chemical formula for lead(IV) acetate is Pb(C2H3O2)4.
The chemical formula of lead acetate is Pb(CH3COO)4.
Pb(OH)4 Hydroxide ion has a charge of -1. Since the lead has a charge of +4, you need four hydroxide ions to keep the compound stable
The periodic symbol for lead is Pb.
The compound name for Pb(OH)4 is lead(IV) hydroxide.
The formula for the ionic compound formed between S^2- and Pb^4+ is PbS2, where lead (Pb) has a 4+ charge and sulfur (S) has a 2- charge. This results in the compound lead(IV) sulfide.
The formula for Plumbic carbonate is Pb(CO3)2 because the higher charge of lead has a charge of 4+ and CO3 has a charge of 2-, therefore the charges would diagonally switch and then be reduced to the simplest whole-number ratio.