nope! its soluble in water (though poorly) and is also soluble in nitric acid
Potassium sulfide, or K2S is a solid and colorless inorganic compound. It readily reacts with water, making it a soluble compound.
Like (almost) ALL kinds of (inorganic) potassium salts it is soluble
The volume is 1,635 L.
K2SO4 is the chemical formula for Potassium sulfate.
10.0 moles K2SO4 (6.022 X 1023/1 mole K2SO4) = 6.02 X 1024 atoms of potassium sulfate ==========================
Potassium sulfide, or K2S is a solid and colorless inorganic compound. It readily reacts with water, making it a soluble compound.
yes, potassium sulfate is a white solid, as long as you keep it cooler than 1956° F.
Like (almost) ALL kinds of (inorganic) potassium salts it is soluble
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is: BaCl2 + K2SO4 -> BaSO4 + 2KCl
The balanced chemical equation for the reaction between potassium iodide and copper sulfate is: 2KI(aq) + CuSO4(aq) → CuI2(s) + K2SO4(aq). In this reaction, a double displacement occurs leading to the formation of insoluble copper iodide and soluble potassium sulfate.
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
The reaction between barium chloride and potassium sulfate results in the formation of insoluble barium sulfate and soluble potassium chloride. This is a double displacement reaction where the cations and anions switch partners. The balanced chemical equation for this reaction is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
There are a total of 4 sulfur atoms in K2SO4.
A solution of K2SO4, which is potassium sulfate, is typically colorless.
The volume is 1,635 L.
K2SO4 + Pbl2 are the reactants.