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What is the concentration of Na2SO4 solution prepared by dissolving 5.35 g of Na2SO4 in sufficient water to give 330 ml of solution?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
How many liters of a 0.250 M BaCl2 solution are needed to react with 0.0325 L of a 0.160 M Na2SO4 solution?
The answer is 20,79 mL (0,021 L).
What volume (in mL) of 0.25M NaSO4 solution is needed to precipitate all the barium as BaSO4(s) from 12.5mL of 0.15M Ba(NO3)2 solution?
The chemical equation is:Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3The volume (in mL) of 0,25M Na2SO4 solution needed to precipitate all the barium as BaSO4(s) from 12,5mL of 0,15M Ba(NO3)2 solution is 7,5 mL.
What are the spectator ions in Bal2 plus Na2SO4?
Na+1 and I-1; the Ba+2 and SO4-2 precipitate as BaSO4.
How many moles of Na SO4 are in 25.0 of this compound?
To find the number of moles of Na2SO4 in 25.0 g of the compound, you need to convert the mass to moles. First, determine the molar mass of Na2SO4, then divide the given mass by the molar mass to obtain the number of moles.
What is the concentration of Na2SO4 solution prepared by dissolving 5.35 g of Na2SO4 in sufficient water to give 330 ml of solution?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
What is the molality of a solution containing 10.0g of Na2SO4 dissolved in 1000.0g of water?
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
What is the pH of 0.25M Na2SO4?
The pH of a solution of Na2SO4 at a concentration of 0.25M is about 7, which is neutral. Na2SO4 is a salt formed from a strong base (NaOH) and a strong acid (H2SO4), so it does not significantly affect the pH of the solution.
What is the pH of Na2SO4?
The pH of a solution of Na2SO4 would be around 7, which is considered neutral. This is because Na2SO4 is a salt that dissociates completely in water to form Na+ and SO4 2- ions, which do not have a significant effect on the pH of the solution.
Will Na2SO4 and benzene form a solution?
No, sodium sulfate (Na2SO4) is not soluble in benzene because it is a polar compound and benzene is a nonpolar solvent. Therefore, they will not form a homogeneous solution.
What is the chemical equation of aqueous solution of sodium sulphite?
As sodium sulfite (Na2SO4) dissolves, it dissociates into its ions: Na2SO4 --> 2Na+ + SO32-
How many sodium ions are present in 325 mL of 0.850 M Na2SO4?
There are 0.850 moles of Na2SO4 in 325 mL of 0.850 M solution. Since Na2SO4 contains 2 sodium ions per formula unit, there will be 2*0.850 moles of sodium ions in the solution. Thus, there are 1.7 moles of sodium ions in 325 mL of 0.850 M Na2SO4 solution.
What is the effect of heating the solution on the particale size of NA2SO4 preciptat?
Seltzer is a solution of a gas(carbon dioxide) and water
What is the boiling point of a 2.35 m solution of sodium sulfate Na2SO4?
103.6ºC
What is the solubility of BaSO4 in a 0.15 M solution of Na2SO4?
(BaSO4 has Ksp = 1.1 x 10-10)-7.3 x 10-10
What is the balanced equation for a reaction between sodium sulfate solution and calcium chloride solution?
Na2SO4 +CaCl2---------------> 2NaCL +CaSo4
What is the balanced chemical equation for reaction for the reaction of a sodium hydroxide solution with sulfuric acid?
Simplified. 2NaOH + H2SO4 -> Na2SO4 + 2H2O
