no
it is sp3d2
The molecule C4H8O2 has 16 valence electrons, which suggests it has sp3 hybridization. This means that the carbon atoms are likely sp3 hybridized, forming sigma bonds with other atoms.
sp3d2
No such thing as 'Xe4' . 'Xe' is Xenon and it exists monatomically. However, it can be forced to combine with fluorine as 'XeF4' (Xenon tetrafluoridie).
Yes, XeF4 has a Lewis structure. Xenon (Xe) is the central atom surrounded by four fluorine (F) atoms. Xenon has 8 valence electrons and forms 4 single bonds with the fluorine atoms, resulting in a square planar geometry.
sp3
The molecule C4H8O2 has 16 valence electrons, which suggests it has sp3 hybridization. This means that the carbon atoms are likely sp3 hybridized, forming sigma bonds with other atoms.
1S2 2S2 2P2, but during the formation of bond with another atom it gets hybridised. example: during the formation of methane(CH4) its outermost shell gets hybridised to SP3.
The correct answer is:BH3 sp2BeCl2 spPCl5 sp3dNH3 sp3SF6 sp3d 2Type your answer here...
In H2O, the central atom is Oxygen atom and it is sp3 hybridised
Prsumably you mean AlH4- the tetrahydroaluminate anion. The hybridization of the central atom of AlH4 is sp3.
The central silicon atom in SiCl4 has a tetrahedral geometry, meaning it is sp3 hybridized. This means that the silicon atom has one s orbital and three p orbitals hybridized to form four equivalent sp3 orbitals for bonding with four chlorine atoms.
carbon can have either sp3 ,sp2 or sp1 hybridised orbital depending upon the type of hybridisation hybridisation influences the bond and bond therapy (strength) in the organic compounds
XeF4 is square planar
Boron in BF4 has an empty p orbital, so it undergoes sp3 hybridization. The boron atom will promote its 2s and two of its 2p orbitals to create four sp3 hybrid orbitals, allowing the boron to form four sigma bonds with the surrounding fluorine atoms.
The formula for xenon tetrafluoride is XeF4.
There are two lone pairs on XeF4.
When XeF4 reacts with water (H2O), the result is the formation of xenon oxyfluoride (XeOF2) and hydrofluoric acid (HF). The balanced chemical equation for this reaction is: XeF4 + 2H2O -> XeOF2 + 4HF