The compound P4O10 is named tetraphosphorus decoxide.
The molar mass of P4O10 is 284.9 g/mol. Therefore, the mass of 5400 moles of P4O10 would be 1,537,848 g or 1537.8 kg.
The compound P4O10 using the stock system is tetraphosphorus decoxide.
To determine the weights of P4O6 and P4O10 produced from the combustion of 31 g of P4 in 32 g of O2, we first need to analyze the reactions. The combustion of phosphorus can produce P4O6 and P4O10, depending on the amount of oxygen available. The balanced equations are: P4 + 6 O2 → 4 P4O6 P4 + 5 O2 → 4 P4O10 Given the 32 g of O2 (which is roughly 1 mol), there is enough oxygen to convert all 31 g of P4 (about 0.5 mol) into either product, but it will favor P4O10 since it requires less oxygen per mole of phosphorus. Therefore, if we assume complete conversion to P4O10, we would produce approximately 60 g of P4O10 (from 31 g of P4).
The chemical symbol for diphosphorus pentoxide is P4O10.
P4O10 + 6H2O = 4H3PO4 Phosphorus oxide reacst with water to produce phosphoric acid.
P4O10 is an acidic compound because it reacts with water to form phosphoric acid (H3PO4).
P4O10 is acidic.
P4O10 - P for Phosphorous, 4 for tetra; O for oxygen, 10 for dec-.
The compound P4O10 is named tetraphosphorus decoxide.
P4O10 is a solid element. It is a combination of phosphorus and oxygen.
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
The molar mass of P4O10 is 284.9 g/mol. Therefore, the mass of 5400 moles of P4O10 would be 1,537,848 g or 1537.8 kg.
The compound P4O10 using the stock system is tetraphosphorus decoxide.
There are 24 mol of P atoms in 96 mol of P4O10. This is because each P4O10 molecule contains 4 P atoms, so you need to divide the total moles of P4O10 by 4 to find the moles of P atoms.
P4O10 is a covalent compound. This is because Phosphorous and Oxygen are both nonmetals.
We first calculate the molar mass of P4O10, which is 284 g/mol. Then we convert the given mass of P4O10 (142 g) to moles using its molar mass. There is a 1:4 molar ratio between P4O10 and O2 in the reaction, so we multiply the moles of P4O10 by 4 to find the moles of O2 needed.