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What is net ionic equation for sodium iodide and silver nitrate when precipitate is formed?

The net ionic equation for the reaction between sodium iodide (NaI) and silver nitrate (AgNO3) when a precipitate is formed is: 2Ag+ + 2I- -> Ag2I (s) This equation represents the formation of silver iodide (AgI) precipitate when silver cations react with iodide anions.


Precipitates can be formed in what kind of reaction?

A precipitate can be a chloride, sulfide, sulfate, phosphate, carbonate etc.


What is the net ionic equation of barium chloride and ammonium sulfate?

The net ionic equation for the reaction between barium chloride (BaCl2) and ammonium sulfate (NH4)2SO4 is Ba2+(aq) + SO4 2-(aq) -> BaSO4(s), where a white precipitate of barium sulfate is formed. The spectator ions, which are not involved in the reaction, are Cl- and NH4+.


What is net ionic equation for sodium sulfate and barium chloride when participate is formed?

The net ionic equation for sodium sulfate (Na2SO4) and barium chloride (BaCl2) when a precipitate of barium sulfate (BaSO4) is formed is: Ba^2+ + SO4^2- → BaSO4 The spectator ions (Na^+ and Cl^-) are not included in the net ionic equation because they do not participate in forming the precipitate.


What does it mean when there is no reaction in an ionic equation?

It means that all the ions are spectators. This happens if no precipitate forms, or no gas or liquid water forms.


What is the net ionic equation for the reaction of silver nitrate and ammonium sulphide?

The net ionic equation for the reaction of silver nitrate (AgNO3) and ammonium sulfide (NH4)2S is: Ag+ + S2- -> Ag2S. This equation represents the formation of silver sulfide precipitate as a result of the reaction.


What is the net inoic equation for the reaction between Na2SO4 and CaCl2?

The net ionic equation for the reaction between Na2SO4 and CaCl2 is: Ca2+ + SO4^2- → CaSO4 This reaction involves the formation of calcium sulfate (CaSO4) precipitate.


What equation is used to determine the precipitate?

Net Ionic


What is the net ionic equation for Mercury II nitrate ammonium sulfide?

The net ionic equation for Mercury(II) nitrate reacting with ammonium sulfide is Hg^2+ (aq) + S^2- (aq) -> HgS (s), where HgS is the solid precipitate formed. The spectator ions, which are not involved in the reaction, are NO3^- and NH4^+.


How do you find the net ionic equation for NaOH and Na2SO4 when they form a precipitate?

The net ionic equation for NaOH and Na2SO4 when they form a precipitate is simple. It will contain only the atoms that participate in the reaction. Both of these compounds are soluble.


What is the net ionic equation of the reaction of zinc bromide and sodium phosphate combine to produce a precipitate?

The net ionic equation for the reaction between zinc bromide (ZnBr2) and sodium phosphate (Na3PO4) to produce a precipitate of zinc phosphate (Zn3(PO4)2) is: 3Zn^2+ + 2PO4^3- -> Zn3(PO4)2 Since all the ions are participating in the reaction, there is no spectator ion to cancel out in this net ionic equation.


What is the net ionic equation for pb(no3)2 and naoh?

The net ionic equation for the reaction between Pb(NO3)2 and NaOH is: Pb2+ + 2OH- → Pb(OH)2(s). This equation represents the formation of a precipitate of lead(II) hydroxide.