First off we multiply .456 by 4 to get it into weight per litre. This gives us 1.824 grams per litre. Next, I'll assume you made a mistake here. Ca is 2+ so you need TWO chlorines (Cl-). I.e. the molecular weight is actually 111g/mol. 1.824/111 is 0.01643 molar. Be careful, because the wrong molecular weight can throw your answer off hugely, especially a heavy atom such as chlorine.
The molarity is 0,125 M.
To find the molarity, first convert the grams of sucrose to moles using its molar mass. Sucrose has a molar mass of 342.3 g/mol. Then, convert the milliliters of solution to liters. Finally, divide the moles of solute by the liters of solution to get the molarity.
To calculate the molarity of a solution, you need to know the number of moles of solute and the volume of the solution in liters. The formula for molarity (M) is M = moles of solute / liters of solution. If you provide the mass of AgNO3 in grams, I can help you calculate the number of moles (using its molar mass) and then determine the molarity.
If 1,1 is grams the molarity is 0,317.
To find the molarity of the solution, first calculate the number of moles of HCl. The molar mass of HCl is approximately 36.46 g/mol, so 14 grams of HCl is about 0.384 moles (14 g ÷ 36.46 g/mol). Molarity (M) is defined as moles of solute per liter of solution, so the molarity of the solution is 0.384 moles ÷ 1.50 liters, which equals approximately 0.256 M.
The molarity is 0,125 M.
.13 (Plato)
The molarity of a solution containing 2 000 grams of H2SO4 in 2500 mL of water is 8,156.
To find the molarity, first convert the grams of sucrose to moles using its molar mass. Sucrose has a molar mass of 342.3 g/mol. Then, convert the milliliters of solution to liters. Finally, divide the moles of solute by the liters of solution to get the molarity.
To calculate the molarity of a solution, you need to know the number of moles of solute and the volume of the solution in liters. The formula for molarity (M) is M = moles of solute / liters of solution. If you provide the mass of AgNO3 in grams, I can help you calculate the number of moles (using its molar mass) and then determine the molarity.
If 1,1 is grams the molarity is 0,317.
The molarity of the solution is 0.5 M.
The molar mass of KF is 58.1 g/mol. Given that there are 116 grams of KF in the solution, this corresponds to 2 moles of KF. Therefore, the molarity of the solution is 2 M.
To find the molarity of the solution, first calculate the number of moles of HCl. The molar mass of HCl is approximately 36.46 g/mol, so 14 grams of HCl is about 0.384 moles (14 g ÷ 36.46 g/mol). Molarity (M) is defined as moles of solute per liter of solution, so the molarity of the solution is 0.384 moles ÷ 1.50 liters, which equals approximately 0.256 M.
To calculate the molarity, you first need to convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is approximately 58.5 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters to get the molarity. In this case, molarity = (58 grams / 58.5 g/mol) / 2.0 L.
Increasing the amount of the solute in the solution the molarity and the density of this solution increases.
First, calculate the molar mass of CaCl2, which is 110.98 g/mol. Next, calculate the number of moles of CaCl2 in 330 grams using the formula moles = mass / molar mass. This gives you 2.97 mol of CaCl2. Finally, divide the moles of CaCl2 by the volume of the solution in liters to get the molarity, which is 2.97 M.