Molarity = moles of solute/Liters of solution Without the solute name the mass ( 8 grams ) does no good. Mass of solute (1 mole/molar mass of solute) = moles solute ----------------------then use Molarity equation. ( remember convert to liters )
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
The 0.5M and 2M refer to moles per liter (of solution). Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L. So find out how many moles the final solution has and divide by 3.0L.First solution (0.5 moles/liter)*(2.5 liter) = 1.25 moles2nd solution (2 moles/liter)*(0.5 liter) = 1 moleMolarity: (1.25 mole + 1 mole)/(3.0 liter) = 0.75 moles/liter = 0.75 M
(100ml)(0.125M NaOH) = (500ml)(X Molarity) Molarity = 0.025 M
The more concentrated solution is the one containing 18 grams of salt and 90 grams of water. This is because the concentration of the solute (salt) is higher in this solution compared to the solution containing 5 grams of salt and 10 grams of water.
The molarity of the solution is calculated using the formula: Molarity (M) = moles of solute / liters of solution. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, plug in the values: M = 2.5 moles / 0.5 L = 5 M. Hence, the molarity of the solution is 5 M.
To calculate the molarity of the solution, first convert the mass of HCl to moles using its molar mass. Then, divide the number of moles by the volume of the solution in liters (500 cm3 = 0.5 L) to get the molarity.
5.0M Molarity is moles of solute/liters of solution. The molar mass of ethanol is 46.07 g/mol, so 115g of ethanol is 2.5 moles of ethanol. 500cc is the same as 0.5L. So 2.5 mol/0.5L = 5.0M
To find the molarity of the KOH solution, we need to know the concentration of the KOH solution in moles per liter. Without this information, we cannot calculate the molarity.
Molarity = moles of solute/Liters of solution Without the solute name the mass ( 8 grams ) does no good. Mass of solute (1 mole/molar mass of solute) = moles solute ----------------------then use Molarity equation. ( remember convert to liters )
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
It depends highly on the compound to be dissolved and the solvent. Molarity is measured my moles per litre, and if you don't know the molar mass of the compound, you can't work out the molarity.
Need moles aluminum oxide first. 51 grams Al2O3 (1 mole Al2O3/101.96 grams) = 0.5002 moles Al2O3 ======================Now, Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters ) Molarity =0.5002 moles Al2O3/0.500 Liters = 1.0 M Al2O3 solution ----------------------------
I assume you mean 0.5 molar, but I'll go with what I'm given. If you have 500 molar of barium chloride, you will have 1000 molar of chloride ions as there are 2 chlorides for every 1 molecule of barium chloride. Having the 100ml there is irrelevant as you are talking about concentration and didn't ask for moles.
The molar mass of NaCl is about 58.44 g/mol. First, convert the mass of NaCl to moles: 3.50 g / 58.44 g/mol = 0.06 mol. Then, calculate the molarity by dividing the moles of solute by the volume of solution in liters: 0.06 mol / 0.5 L = 0.12 M.
molarity of a solution means mols per liter.First, you need to convert 23 grams on NaCl into mols. 23g divided by molar mass (58.44g/mol) which gives you .394 mols.Now, you need to convert 500ml to L which moves the decimal three places to the left, giving you .500L of solution.Finally, divide the mols over solution to get .787M
To find the number of moles of sulfuric acid in the solution, multiply the volume of the solution (in liters) by the molarity. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, multiply 0.5 L by 0.324 mol/L to get 0.162 moles of sulfuric acid in 500 mL of the 0.324 M solution.