In 500ml there are 3.5 grams. Therefore in 1 litre, there are 7g. 7/58.443 is 0.1198 molar.
5.0
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
[117(g NaCl) / 58.5(g NaCl/mol NaCl)] / 40.0(L solution) = [117/58.5]/40.0 = 2.00(mol NaCl) / 40.0(L) = 0.0500 mol NaCl / L solution = 0.0500 M
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
Pretty concentrated! ( I assume you mean 2.3 Liters )First get the moles of sodium chloride.456 grams NaCl (1 mole NaCl/58.44 grams)= 7.803 moles NaCl==============Now,Molarity = moles of solute/Liters of solutionMolarity = 7.803 moles NaCl/2.3 Liters= 3.4 M NaCl solution----------------------------
5.0
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
[117(g NaCl) / 58.5(g NaCl/mol NaCl)] / 40.0(L solution) = [117/58.5]/40.0 = 2.00(mol NaCl) / 40.0(L) = 0.0500 mol NaCl / L solution = 0.0500 M
Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
Need to find moles NaCl. 526 grams NaCl (1 mole NaCl/58.44 grams) = 9.0 moles NaCl --------------------------------now, Molarity = moles of solute/Liters of solution or, for our purposes Liters of solution = moles of solute/Molarity Liters of solution = 9.0 moles NaCl/3.0 M = 3.0 liters in volume ---------------------------------
molarity of 5% NaCl solution would be 1.25M.
1.7M
Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------
Pretty concentrated! ( I assume you mean 2.3 Liters )First get the moles of sodium chloride.456 grams NaCl (1 mole NaCl/58.44 grams)= 7.803 moles NaCl==============Now,Molarity = moles of solute/Liters of solutionMolarity = 7.803 moles NaCl/2.3 Liters= 3.4 M NaCl solution----------------------------