Pretty concentrated! ( I assume you mean 2.3 Liters )
First get the moles of sodium chloride.
456 grams NaCl (1 mole NaCl/58.44 grams)
= 7.803 moles NaCl
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Now,
Molarity = moles of solute/Liters of solution
Molarity = 7.803 moles NaCl/2.3 Liters
= 3.4 M NaCl solution
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Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
.62 M is the molarity of the solution made by dissolving 22.4 g of LiClO4 3H2O in 225 mL of water.
Divide grams (mass) by molar mass to find moles58.44 (g NaCl/L) / [22.99+35.45](g NaCl/mol NaCl)= 1.000 mol/L NaCl
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
Divide 175 by 750 and multiply by 1000 to get g/l. This gives you 233.3333g/litre. The molecular weight for KNO3 is 101.1g/mol. 233.333/101.1 is 2.31 molar.
molarity of 5% NaCl solution would be 1.25M.
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------
.62 M is the molarity of the solution made by dissolving 22.4 g of LiClO4 3H2O in 225 mL of water.
concentration or molarity = number of moles/volume number of moles (n) = mass in grams of nacl/relative atomic mass of nacl n=17.52/(23+35.5) n = 0.2994872 mol volume = 2000/1000 = 2dm^3 molarity = 0.2994872/2 =0.15mol/dm^3
Divide grams (mass) by molar mass to find moles58.44 (g NaCl/L) / [22.99+35.45](g NaCl/mol NaCl)= 1.000 mol/L NaCl
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
29g/150*1000 is 193.333g. The molecular weight of NaCl is 58.433. Therefore 193.333/58.433 is 3.31 molar.
Divide 175 by 750 and multiply by 1000 to get g/l. This gives you 233.3333g/litre. The molecular weight for KNO3 is 101.1g/mol. 233.333/101.1 is 2.31 molar.
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------