40075
No. Saudia Arabia is north of the equator.
say mass(m) = 100 kgvelocity(v) at equator = 464.6 metres / secondradius(r) to earth surface = 6 371 000 metresacceleration due to gravity (g) = 9.82 (m / s) / s.the force of attraction (f) anywhere on earths surface, = m * g = 100 * 9.82 = 982 newtons.the force of repulsion / centripetal force (f) at the equator = mass * (v^2) / r =3.39 newtons
Gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles. This means an object will weigh about 0.5% more at the poles than at the Equator.
The Sun has a volume of 1.4122×10^27 m³ (1,300,000 Earths) Saturn has a volume of 8.2713×10^14 km³ (763.59 Earths) So, approximately 1,702 Saturns could fit inside the Sun if it were a hollow space.The Sun has a volume of 1.4122×10^27 m³ (1,300,000 Earths)Saturn has a volume of 8.2713×10^14 km³ (763.59 Earths)So, approximately 1,702 Saturns could fit inside the Sun if it were a hollow space.
Gravity strengths at the equator for each of the planets is as follows, measured in g's, where 1 g is the standard earth gravity; Mercury = 0.38 (or 38% that of earths) Venus = 0.904 Earth = 0.99732 Mars = 0.376 Jupiter = 2.528 Saturn = 1.065 Uranus = 0.886 Neptune = 1.14
A meter is a measure of length, not area. The equator is approximately 40,000,000 m long, so one meter is 1 forty millionth of the equator.
moon
106 pounds Saturn's gravity acceleration at the equator is about 10.4 m/s2. Earths gravity acceleration is 9.81 m/s2. So Saturn's gravity is about 10.4/9.81 = 1.06 times stronger than Earth's. That would put a weight of 100 lb on Earth, on 106 lb on the surface of Saturn at the equator.
the earth at its equator 1 m=100 cm 13cm=0.13 m
Gravity is pretty constant figure anywhere on earth, essentially its dependent on your distance from the center of gravity of the earth, nominally it will produce an acceleration of 9.81((m/s/)/s) at the earths surface. Gravity is dependent on mass and independent of motion , ie mass of earth attracting mass of person , attraction being proportional to total mass of both and distance between their centers of gravity. However , a very small opposing acceleration outwards is experienced because you are rotating about the earths axis (centrifugal action) , its maximum effect is on the equator and zero effect at the poles. this acceleration can be calculated from: a = (v^2)/r where: a = acceleration ((m/s)/s) v = velocity (m/s) r = radius or normal distance from earths axis (m)
say your mass (m) is 100 kgvelocity (v) at equator = 40 030 000 / 86164 = 464.6 metres / secearth radius(r) = 6 371 000 metresacceleration due to gravity at earths surface (g) = 9.82 (m/s)/s.gravity force at earth surface ( f = m * g) = 100 * 9.82 = 982 newtons.centripetal force at equator f = m * ((v^2)/r)f = 100 * ((464.6^2)/6 371 000)f = 3.39 newtons
Force (newtons) = mass (kg) * acceleration (m/s/s) > Acceleration at earths surface radius = 9.82 m/s/s
No. Saudia Arabia is north of the equator.
The centripetal acceleration experienced at the equator due to the Earth's rotation is approximately 0.034 m/s.
The (tangential) velocity of a point at the equator is v=465 m/s. The acceleration of gravity g is diminished by v2/R = 0,033 (m/s2), where R is the earth radius which is 6.400 km approximately.
As long as you like. 10 sqm is a measure of area. In the form of a rectangle, it could be 1 m * 10 m which would make it 10 m long. But it could also be 0.1 m * 100 m making it 100 m long or 0.01 m * 1000 m making it 1000 m long or 0.001 m * 10000 m making it 10000 m long. There is no limit to its length.
they are both near the equator, correct me if i m wrong.