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Where should you stand on the earth's surface to experience the least centripetal acceleration Explain?
As the earth bulges a bit at the equator, you should stand at the poles to experience the most centripetal acceleration. Looking at the formula for centripetal acceleration (Ac= v2/r), we see that as the distance from the centre of the body (r) increases, the acceleration decreases, therefore when the distance to the centre mass is smaller, as it is at the poles compared to at the equator, the acceleration is greatest.
Why does the weight of an object change when it is moved from the equator to the poles?
The weight of an object changes when it is moved from the equator to the poles due to the variation in gravitational force caused by the Earth's rotation. The force of gravity is slightly stronger at the poles compared to the equator, leading to a small change in weight.
What is the value of acceleration due to gravity g in Dublin Ireland?
The acceleration of gravity (9.80 meters per second squared) does vary a bit with latitude because of the effects of centripetal acceleration as well as differences in the Earth's polar and equatorial diameters.1 But the variance isn't noticeable until the third significant figure. The acceleration due to gravity will be somewhat less in Dublin than at the equator because Dublin's latitude is 53 degrees, 20 minutes North Latitude, closer to the pole than the equator. To calculate a more precise value (more precise than just 9.80 m/s2) would require you to know the radius of the Earth at your location, since g = GMe/Re, where G is the universal gravitation constant, Me is the mass of the Earth, and Re is the radius of the Earth. From that you would substract the centripetal acceleration, which can also be calculated based upon your latitude. (Which is an answer to another question that hasn't been asked yet!) _________ 1. The Earth is not a perfect sphere. The equatorial diameter is greater than the polar diameter. Hence, g will be slightly greater at the poles than at the equator. And because the Earth rotates, the acceleration of gravity will be reduced by the centripetal acceleration, which is greatest at the equator. So, if oyu want to lose weight, move from Dublin to Ecuador.
Is there any difference between the value of g at the equator and the poles?
Yes, there is a difference in the value of acceleration due to gravity (g) at the equator and the poles. This is because the Earth is not a perfect sphere and has an oblate shape. At the equator, the centrifugal force due to the Earth's rotation reduces the effective gravity and makes g slightly smaller compared to the poles where this effect is minimal.
How does the rotation of the Earth affect its shape?
The rotation of the Earth causes it to bulge slightly at the equator, making it slightly flattened at the poles and slightly wider at the equator. This shape is known as an oblate spheroid.
Where should you stand on the earth's surface to experience the least centripetal acceleration Explain?
As the earth bulges a bit at the equator, you should stand at the poles to experience the most centripetal acceleration. Looking at the formula for centripetal acceleration (Ac= v2/r), we see that as the distance from the centre of the body (r) increases, the acceleration decreases, therefore when the distance to the centre mass is smaller, as it is at the poles compared to at the equator, the acceleration is greatest.
Where on the surface of the earth should you stand to experience the least centripetal acceleration?
Hello, To answer the question, the place where one would experience the least amount of centripetal acceleration would be at either the north or south pole. If you think about it, the part of the Earth that the spins the fastest is at the Equator. The North and South poles move the least while the Earth spins. Centripetal Force is all about making sure that a object on a spinning sphere keeps going around in a circle. If the object spins at a greater rate, the centripetal acceleration would be larger because there is more of a "pull" to keep the object in line.
Why does the weight of an object change when it is moved from the equator to the poles?
The weight of an object changes when it is moved from the equator to the poles due to the variation in gravitational force caused by the Earth's rotation. The force of gravity is slightly stronger at the poles compared to the equator, leading to a small change in weight.
When earth angular velocity increase then gravitational acceleration increase?
Let's be very accurate when describing accelerations in this question. Consider a person at the equator. The gravitational force of attraction on him is constant whether or not the earth is rotating. This acceleration is called the acceleration due to gravity (ag) Now, since the earth is rotating about its axis, there has to be a centripetal force on the person. It is the gravitational force which provides the centripetal force. Thus, there is a centripetal acceleration on the person (ac) Finally, the rest of the gravitational force causes the person to accelerate towards earth. This is called the acceleration of free fall (af) This gives ag = ac + af ac is given by the equation: ac = w2r where w is the angular velocity and r is the radius of rotation If the angular velocity of the earth increases, centripetal acceleration will increase. af = ag - w2r Therefore, the acceleration of free fall will decrease.
Why is the centrifugal acceleration decrease from the equator to the poles?
The relevant formula here is:centrifugal acceleration = omega squared x radiusomega (the angular speed) doesn't change in this formula (for the situation under consideration), but "radius", the distance from the axis of rotation, does.
Why would an object way less at the equator than at the poles?
Not for sure but it seems like there would be more gravity at the equator than at the poles. The earth rotates and creates a centrifugal acceleration at the equator the counters the force of gravity. acceleration due to gravity =GM/R2 acceleration due to rotation =V2/R So gravity at the equator is GM/R2 - V2/R
Are people living at the equator constantly accelerating?
No, people living at the equator are not constantly accelerating. The only acceleration they would experience is due to the Earth's rotation, which is a constant speed.
How does rotation affect the value of gravity at the earth surface?
The (centripital) force due to rotation is at its greatest at the equator, if you weigh 100 kg, the force of gravity on you = approx. 982 n anywhere on earths surface, the centripetal force at the equator = 3.4 n
The acceleration due to gravity at the equator?
about 9.795m/s2 but9.8m/s2 is almost always used.Note: centripetal acceleration (from the earth's spin) cause apparent gravity to be about 0.3% less than actual gravity (about 9.767m/s2) at the equatoryou can find the acceleration of gravity on any planet by the equation:a=G(M/R2) where 'a' is the acceleration due to gravity, G is the gravitational constant (about .0000000000667), M is the mass of the earth ( or other planet), and R is the radius of the earth (or other planet)References:A.P. Physics class
Where is gravity strongest equator or north pole?
Force of gravity is proportional to the masses and inversely proportional to the square of the distance. Only considering the force of gravity, it is larger at the equator. If you measure the weight of an object, however, countering gravity is the centripetal force of rotation, which will "subtract" from the force of gravity at the equator.
Why is gravity stronger at the poles than the equator?
Gravity is stronger at the poles than the equator because of the Earth's shape. The Earth is an oblate spheroid, meaning it is slightly flattened at the poles and bulges at the equator due to its rotation. This bulging at the equator causes objects to be farther away from the center of the Earth, resulting in weaker gravitational pull compared to the poles.
How many seasons are experienced on the equator?
4 seasons are experienced on the equator
