True, at relatively low speeds, if the projectile was launched at maybe the speed of light, improbable as it is, this may give it enough momentum to carry on past the point were the planet's gravity has a large effect on its motion and therefore carry on moving away from the planet until stopped by another force, however, even if the initial velocity of the projectile is the same as that planets escape velocity (the speed it needs to travel at to leve the planet) this speed is not constant and the projectile will feel a very large force from the gravity of the planet and hence be brought back down to its surface
Range of a projectileThe path of this projectile launched from a height y0 has a range d.In physics, a projectile launched with specific initial conditions in a uniform gravity field will have a predictable range. As in Trajectory of a projectile, we will use:g: the gravitational acceleration-usually taken to be 9.80 m/s2 (32 f/s2) near the Earth's surfaceθ: the angle at which the projectile is launchedv: the velocity at which the projectile is launchedy0: the initial height of the projectiled: the total horizontal distance travelled by the projectileWhen neglecting air resistance, the range of a projectile will beIf (y0) is taken to be zero, meaning the object is being launched on flat ground, the range of the projectile will then simplify toso to increase the range θ shoud vary from 0 to 45 and after 45 it starts decreasing.
The range of a projectile is influenced by both the initial velocity and launch angle, while the height of the projectile is affected by the launch angle and initial height. Increasing the launch angle typically decreases the range but increases the maximum height of the projectile.
9 km/s = 9000m/s Gravity decreases the velocity of the object by 9.8 m/s each second. The velocity at the top is 0 m/s Equation 1: Velocity final = velocity initial - (9.8 m/s × time) Final velocity =0 m/s Initial velocity = 9000m/s 0 = 9000 - 9.8 t 9.8 t = 9000 t = 9000÷ 9.8 t = 918 seconds Average velocity = (9000 + 0 ) ÷ 2 =4500 m/s Height = average velocity × time Height = 4500 m/s ×918 seconds=4,131,000 meters = 4,131 Km. If you do not want to round, this equation will find the answer more accurately. (velocity final) 2 - (velocity initial) 2 = 2 × acceleration × distance m/s2 0 - 90002 = 2 × 9.8 × d d = 4,132,653.061 meters = 4,132.653061Km I do not know of any measuring tool that measures that precisely!
false....just by velocity the projection cannot be maximum.....for maximum projection the angle at which the projection is made and location would play a big role....ie..if two rockets are fired one from equator and one from pole with same velocity and same angle....the rocket fired from pole will have maximum projectile as it has to pass through less atmosphere hence less resistant....
You cannot. You need to know either the initial speed or angle of projection (A).
No, a projectile velocity is the initial velocity at which a projectile is launched. The highest velocity a projectile can reach depends on factors such as air resistance, gravity, and propulsion force. In some cases, the velocity of a projectile can increase or decrease after it is launched.
The formula for the horizontal distance traveled by a horizontally launched projectile is: range = initial velocity * time. This formula assumes that there is no air resistance and that the projectile is launched horizontally.
The initial direction of a projectile's velocity is typically determined by the angle at which it is launched relative to the horizontal plane. This angle will influence both the horizontal and vertical components of the velocity.
The horizontal distance traveled by a projectile is determined by the initial velocity of the projectile, the angle at which it was launched, and the time of flight. It can be calculated using the equation: horizontal distance = (initial velocity * time * cosine of launch angle).
Some of the factors that determine the movements of a projectile include: air resistance, force of gravity, initial launch velocity, the angle a projectile was launched at, and the objects initial elevation.
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
The horizontal and vertical components of velocity for a projectile launched at an angle between 0 and 90 degrees are independent of each other. The horizontal velocity remains constant throughout the motion, while the vertical velocity changes due to the effect of gravity. The initial velocity of the projectile is divided into these two components based on the launch angle.
A projectile that is launched at a lower initial velocity but at a higher angle will spend more time in the air compared to one launched at a higher velocity but at a lower angle. This is because the projectile launched at a higher angle will have a longer time of flight as it reaches a higher altitude.
The minimum initial velocity required for a projectile to reach a target 90 km away depends on the angle at which the projectile is launched, as well as the effects of air resistance and other factors. A common approach is to use projectile motion equations to determine the initial velocity needed for the projectile to cover the horizontal distance of 90 km in the given conditions.
To determine the vertical velocity of a projectile, you can use the formula: vertical velocity initial vertical velocity (acceleration due to gravity x time). The initial vertical velocity is the speed at which the projectile is launched upwards or downwards. Acceleration due to gravity is typically -9.8 m/s2 (negative because it acts downwards). Time is the duration for which the projectile has been in motion. By plugging in these values, you can calculate the vertical velocity of the projectile.
A projectile has an initial forward velocity.
To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it was launched, and the acceleration due to gravity. Using these values, you can calculate the horizontal distance traveled using the projectile motion equations.