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True or false the larger the initial velocity the higher a projectile will go above a planets surface?
false....just by velocity the projection cannot be maximum.....for maximum projection the angle at which the projection is made and location would play a big role....ie..if two rockets are fired one from equator and one from pole with same velocity and same angle....the rocket fired from pole will have maximum projectile as it has to pass through less atmosphere hence less resistant....
What else can I help you with?
True or false Independent of initial velocity a projectile will always fall back to the surface of the planet it is launched from?
True, at relatively low speeds, if the projectile was launched at maybe the speed of light, improbable as it is, this may give it enough momentum to carry on past the point were the planet's gravity has a large effect on its motion and therefore carry on moving away from the planet until stopped by another force, however, even if the initial velocity of the projectile is the same as that planets escape velocity (the speed it needs to travel at to leve the planet) this speed is not constant and the projectile will feel a very large force from the gravity of the planet and hence be brought back down to its surface
If at the Earth's surface a projectile is launched straight up at a speed of 9 km per sec to what height will it rise Ignore air resistance and the rotation of the Earth?
9 km/s = 9000m/s Gravity decreases the velocity of the object by 9.8 m/s each second. The velocity at the top is 0 m/s Equation 1: Velocity final = velocity initial - (9.8 m/s × time) Final velocity =0 m/s Initial velocity = 9000m/s 0 = 9000 - 9.8 t 9.8 t = 9000 t = 9000÷ 9.8 t = 918 seconds Average velocity = (9000 + 0 ) ÷ 2 =4500 m/s Height = average velocity × time Height = 4500 m/s ×918 seconds=4,131,000 meters = 4,131 Km. If you do not want to round, this equation will find the answer more accurately. (velocity final) 2 - (velocity initial) 2 = 2 × acceleration × distance m/s2 0 - 90002 = 2 × 9.8 × d d = 4,132,653.061 meters = 4,132.653061Km I do not know of any measuring tool that measures that precisely!
What is the surface characteristics of a crater?
The surface characteristics of a crater typically include a bowl-shaped depression with raised rims. The interior may have radial and concentric ridges, terraces, and central peaks, while the surrounding area may show ejecta deposits and rays. The surface may also bear signs of slumping, landslides, and other erosion processes.
Can you describe the surface of the Jovian planets?
The Jovian planets are gas giants and have no surface.
Why are inner planets also called rocky planets?
The inner planets, except earth, are made up of rocks. They have a hard surface. The earth would be one of these except we have water. The outer planets are gas giants and do not have a solid surface.
True or false Independent of initial velocity a projectile will always fall back to the surface of the planet it is launched from?
True, at relatively low speeds, if the projectile was launched at maybe the speed of light, improbable as it is, this may give it enough momentum to carry on past the point were the planet's gravity has a large effect on its motion and therefore carry on moving away from the planet until stopped by another force, however, even if the initial velocity of the projectile is the same as that planets escape velocity (the speed it needs to travel at to leve the planet) this speed is not constant and the projectile will feel a very large force from the gravity of the planet and hence be brought back down to its surface
Ignoring air resistance what is the minimum initial speed a projectile must have at the Earths surface if the projectile is to escape the Earths gravitational pull?
The minimum initial speed for a projectile to escape Earth's gravitational pull (escape velocity) is about 11.2 km/s. This speed is independent of the mass of the projectile and is based on the balance between the projectile's kinetic energy and gravitational potential energy. Any speed greater than the escape velocity will allow the projectile to escape Earth's gravitational pull.
What is the maximum height reached by a projectile shot straight up from the Earth's surface at a speed of 1.10104 km/hr?
The maximum height reached by a projectile shot straight up from the Earth's surface at a speed of 1.10104 km/hr is determined by the formula: Maximum height (initial velocity)2 / (2 acceleration due to gravity) Given that the initial velocity is 1.10104 km/hr, we can convert this to m/s by multiplying by 1000/3600. The acceleration due to gravity is approximately 9.81 m/s2. Plugging in the values, we can calculate the maximum height reached by the projectile.
If at the Earth's surface a projectile is launched straight up at a speed of 9 km per sec to what height will it rise Ignore air resistance and the rotation of the Earth?
9 km/s = 9000m/s Gravity decreases the velocity of the object by 9.8 m/s each second. The velocity at the top is 0 m/s Equation 1: Velocity final = velocity initial - (9.8 m/s × time) Final velocity =0 m/s Initial velocity = 9000m/s 0 = 9000 - 9.8 t 9.8 t = 9000 t = 9000÷ 9.8 t = 918 seconds Average velocity = (9000 + 0 ) ÷ 2 =4500 m/s Height = average velocity × time Height = 4500 m/s ×918 seconds=4,131,000 meters = 4,131 Km. If you do not want to round, this equation will find the answer more accurately. (velocity final) 2 - (velocity initial) 2 = 2 × acceleration × distance m/s2 0 - 90002 = 2 × 9.8 × d d = 4,132,653.061 meters = 4,132.653061Km I do not know of any measuring tool that measures that precisely!
What are the factors influencing projectile motion?
The motion of a projectile can be completely described in terms of ...the direction in which it is launchedits speed at launchthe local acceleration of gravityplus, if air resistance is to be taken into account ...the projectile's size, shape, weight, mass distribution, composition, and surface texturethe temperature, pressure, humidity, wind speed, and turbulence parametersof the air it encounters at every point in its trajectory.That's why air resistance is always ignored for simple exercises in projectile motion.
How are the four gas planets similar?
No solid surface and high velocity winds.
What type of path does a projectile follow in the absence of air resistance?
Without air resistance, the path of a projectile over a small part of the Earth's surface, under the influence of gravity alone, is always a piece of a parabola ... as long as it's not launched straight up or straight down.
A rocket of initial mass m0 is shot vertically upward Assume that the motion occurs under constant gravitational acceleration g Let the initial velocity of the rocket on the surface of the earth be?
the initial velocity of the rocket is zero.
How do you find projectile motion?
Projectile motion is a form of motion in which a projectile is thrown near the earth's surface. When thrown, the projectile moves along a curved path because of gravity. An example of projectile motion is a sprinkler shooting water into the air and the water falling back down to Earth.
Which is the total velocity of a projectile at maximum height?
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
Projectile's vertical velocity component changes at a constant?
The vertical velocity component of a projectile changes at a constant rate due to the acceleration of gravity. This acceleration causes the projectile to speed up as it moves downward and slow down as it moves upward. The magnitude of the acceleration is constant near the Earth's surface, at approximately 9.8 m/s^2.
A rocket that moves upward from earth's surface at escape velocity will?
Escape the earth's gravitational pull and continue out into space. However, a rocket does not need to be launched at the escape velocity as it can continue to accelerate as it climbs. A gun projectile would need to be fired with the escape velocity. In a perfect system with only the projectile and the Earth: If the projectile is fired with the exact escape velocity it will travel to infinity away from the Earth. Upon reaching infinitely far away from Earth the projectile would have zero velocity. All of its kinetic energy (movement) would be transferred to potential energy.
