To find the mass of 0.555 mol of magnesium fluoride (MgF₂), first determine the molar mass. The molar mass of Mg is approximately 24.31 g/mol, and that of F is about 19.00 g/mol, giving MgF₂ a total molar mass of about 24.31 + (2 × 19.00) = 62.31 g/mol. Therefore, the mass of 0.555 mol of MgF₂ is calculated as 0.555 mol × 62.31 g/mol ≈ 34.59 g.
The molecular mass of magnesium in magnesium chloride is 24.305 grams/mol.
To find the percent composition of magnesium (Mg) in magnesium oxide (MgO), first determine the molar masses: magnesium has a molar mass of approximately 24.31 g/mol, and oxygen has a molar mass of about 16.00 g/mol. The molar mass of MgO is roughly 40.31 g/mol (24.31 g/mol + 16.00 g/mol). The percent composition of magnesium is then calculated as (24.31 g/mol / 40.31 g/mol) × 100%, which equals approximately 60.3%.
To calculate the mass of 2.25 moles of magnesium sulfide (MgS), first determine its molar mass. Magnesium (Mg) has a molar mass of approximately 24.31 g/mol, and sulfur (S) has a molar mass of about 32.07 g/mol. Therefore, the molar mass of MgS is 24.31 g/mol + 32.07 g/mol = 56.38 g/mol. Multiplying the molar mass by the number of moles gives: 2.25 moles × 56.38 g/mol = 127.78 grams.
To find the percent composition of magnesium in magnesium chromate (MgCrO4), first calculate the molar mass of the compound. The molar mass of magnesium (Mg) is approximately 24.31 g/mol, chromium (Cr) is about 51.996 g/mol, and oxygen (O) is about 16.00 g/mol. Thus, the molar mass of MgCrO4 is 24.31 + (2 × 51.996) + (4 × 16.00) = 200.31 g/mol. The percent composition of magnesium is calculated as (24.31 g/mol ÷ 200.31 g/mol) × 100%, which is approximately 12.13%.
The molar mass of MgS (magnesium sulfide) is calculated by adding the atomic masses of magnesium (Mg) and sulfur (S). The atomic mass of Mg is approximately 24.31 g/mol, and S is approximately 32.06 g/mol. Therefore, the molar mass of MgS is approximately 24.31 + 32.06 = 56.37 g/mol.
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
The molecular mass of calcium fluoride is 78,07 g.
MgF2 has a molecular weight of 24+19*2 = 62g. Thus, 31 grams of MgF2 represent .5mol. There are 6.022*10^23 particles per mole. Since MgF2 has three atoms in it, we can find the number of atoms by the following: (.5 mol)(6.022*10^23 particles/mol)(3 atoms in MgF2) = ... Enjoy your free high school chemistry answer!
The molecular mass of magnesium in magnesium chloride is 24.305 grams/mol.
To calculate the fluoride concentration in parts per million (ppm) in a solution, you can use the formula: Fluoride concentration (ppm) (mass of fluoride in solution / volume of solution) x 1,000,000 First, determine the mass of fluoride in the solution by multiplying the concentration of fluoride ions (in mol/L) by the molar mass of fluoride (18.998 g/mol) and the volume of the solution in liters. Then, divide the mass of fluoride by the volume of the solution and multiply by 1,000,000 to get the concentration in ppm.
To calculate the mass of 2.25 moles of magnesium sulfide (MgS), first determine its molar mass. Magnesium (Mg) has a molar mass of approximately 24.31 g/mol, and sulfur (S) has a molar mass of about 32.07 g/mol. Therefore, the molar mass of MgS is 24.31 g/mol + 32.07 g/mol = 56.38 g/mol. Multiplying the molar mass by the number of moles gives: 2.25 moles × 56.38 g/mol = 127.78 grams.
To find the mass of 24.6 formula units of magnesium oxide, we first need to determine the molar mass of magnesium oxide. Magnesium has a molar mass of approximately 24.3 g/mol, and oxygen has a molar mass of approximately 16.0 g/mol. Therefore, the molar mass of magnesium oxide (MgO) is 24.3 + 16.0 = 40.3 g/mol. Next, we multiply the molar mass of MgO by the number of formula units (24.6) to find the total mass: 40.3 g/mol x 24.6 = 992.38 grams. Therefore, the mass of 24.6 formula units of magnesium oxide is approximately 992.38 grams.
The formula for magnesium cyanide is Mg(CN)2. To find the molar mass, you would add the molar mass of one magnesium atom (24.305 g/mol), and two cyanide ions (26.02 g/mol each). Therefore, the molar mass of magnesium cyanide is 76.345 g/mol.
The formula mass of magnesium phosphate (Mg3(PO4)2) is calculated by adding the atomic masses of each element in the formula. The atomic mass of magnesium (Mg) is approximately 24.31 g/mol, phosphorus (P) is about 30.97 g/mol, and oxygen (O) is around 16.00 g/mol. Therefore, the formula mass of magnesium phosphate is approximately 262.86 g/mol.
To find the mass of oxygen gas released, we can first find the mass of magnesium in 16.12 g of magnesium oxide (molar mass of MgO = 40.31 g/mol) and then subtract it from 9.72 g to find the mass of oxygen. Find the moles of magnesium in 16.12 g of MgO: 16.12 g / 40.31 g/mol = 0.4 mol Mg Mg and O are in a 1:1 molar ratio in MgO, so 0.4 mol of Mg is equal to 0.4 mol of O Calculate the mass of oxygen: 0.4 mol x 16 g/mol = 6.4 g Therefore, 6.4 g of oxygen gas is also released in the reaction.
To calculate the number of moles in 165 g of magnesium, we first need to find the molar mass of magnesium, which is 24.305 g/mol. Then, we divide the given mass by the molar mass to find the number of moles. So, 165 g / 24.305 g/mol ≈ 6.79 moles of magnesium.
Sodium iodide has the highest molar mass among the compounds listed, with a molar mass of 149.89 g/mol. Sodium bromide has a molar mass of 102.89 g/mol, sodium chloride has a molar mass of 58.44 g/mol, lithium bromide has a molar mass of 86.85 g/mol, and lithium fluoride has a molar mass of 25.94 g/mol.