0
The numbers (1 and 2) are subscripts such as p1v1. The subscript numbers distiquish them from others of the same letter that are going to be used in the same equation. In this case there are probably 2 Pressure variables and 2 Volume variables. Since you want to use p and v for pressure and volume but there are pressures and volumes at let's say different gauges in the system then we have to distiguish the two. p1 = pressure read from gauge one and v2 is volume read from gauge 2. This, among others, is part of the energy equation for thermodynamics p1v1 = p2v2. The P is for pressure and the V is for Volume.
_______________________________________________________________________
My answer
This occurs to Boyle's Law.
What else can I help you with?
What happens to the pressure of a gas when the volume of the container double in size?
You have for an Ideal Gas:PV = mRT/M( P2 ) ( V2 )/ (T2 ) ( m2 ) = ( P1 ) ( V1 ) / ( m1 ) ( T1 ) = R/M = ConstantV2 = ( V1 ) ( P1 /P2 ) ( T2/T1 ) ( m2 /m1 )You have :( P1 / P2 ) = 1.00( T2 / T1 ) = 1.00( m2 / m1 ) = 2.00V2 = ( V1 ) ( 1.000 ) ( 1.000 ( 2.000 ) = ( 2.000 ) ( V1 )
What does G2 P1 T1 mean in GYN?
In gynecology (GYN), G2 P1 T1 refers to a woman who has been pregnant twice (G2), had one live birth (P1), and one term birth (T1). This shorthand terminology is used to quickly convey a woman's obstetric history.
What is the final pressure of a 2.00 ATM gas container that increased in temperature from 299 K to 333 K while the volume increased from 650 mL to 850 mL?
P1 = 2T1 = 299T2 = 333V1 = 0.65V2 = 0.85P2t = P1 * T2 / T1 = 2.227 ATMP2v = P1 * V1 / V2 = 1.529 ATMP2 = P2t * P2v = 3.41 ATM
A sample of oxygen gas has a volume of 150 milliliters at 300k if the pressure of the sample is held constant and the temp raised to 600k the new sample will be?
Using the combined gas law (P1V1/T1 = P2V2/T2), we can calculate the new volume of the oxygen gas sample at 600K. Given P1V1/T1 = P2V2/T2, we have P1 = P2 (pressure is constant), V1 = 150 mL, T1 = 300K, and T2 = 600K. Plugging in these values, we get V2 = (P1 * V1 * T2) / (T1) = (1 * 150 * 600) / (300) = 300 mL. So, the new volume of the oxygen gas sample at 600K would be 300 milliliters.
A sample of helium gas at 25 celsius is compressed from 200mL to 0.240 mL Its pressure is now 300mm Hg What was the original pressure of the helium?
To solve for the original pressure of the helium gas, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. Using this law, we can set up the equation (P1)(V1) = (P2)(V2), where P1 is the original pressure, V1 is the original volume, P2 is the final pressure, and V2 is the final volume. Plugging in the values gives us (P1)(200 mL) = (300 mm Hg)(0.240 mL). Solving for P1 gives us P1 = (300 mm Hg)(0.240 mL) / 200 mL = 0.36 mm Hg. Therefore, the original pressure of the helium gas was 0.36 mm Hg.
What happens to the pressure of a gas when the volume of the container double in size?
You have for an Ideal Gas:PV = mRT/M( P2 ) ( V2 )/ (T2 ) ( m2 ) = ( P1 ) ( V1 ) / ( m1 ) ( T1 ) = R/M = ConstantV2 = ( V1 ) ( P1 /P2 ) ( T2/T1 ) ( m2 /m1 )You have :( P1 / P2 ) = 1.00( T2 / T1 ) = 1.00( m2 / m1 ) = 2.00V2 = ( V1 ) ( 1.000 ) ( 1.000 ( 2.000 ) = ( 2.000 ) ( V1 )
How do you find T2 of the combined gas law?
The Combined Gas Law relates pressure (P), volume (V) and temperature (T). The appropriate SI units are P in atm, V in liters, and T in degrees Kelvin. The Combined Gas Law equation is (P1*V1)/T1 = (P2V2)/T2. Isolating for V2 the equation then becomes (P1V1T2)/(T1P2) = V2
At standard temperature a gas has a volume of 350 mL the temperature is then increased to 137 C and the pressure is held constant What is the new volume?
T1 = 273.15K. T2 = 410.15K. V1 = 350mL. V2 = ? P1 = P2. Since pressure is constant you can use the formula. V1/T1 = V2/T2 Rearrange the formula to get: V2 = T2V1/T1
What is gay lussacs law formula?
Gay-Lussac's Law states that the pressure of a sample of gas at constant volume, is directly proportional to its temperature in Kelvin. The P's represent pressure, while the T's represent temperature in Kelvin. P1 / T1 = constant After the change in pressure and temperature, P2 / T2 = constant Combine the two equations: P1 / T1 = P2 / T2 When any three of the four quantities in the equation are known, the fourth can be calculated. For example, we've known P1, T1 and P2, the T2 can be: T2 = P2 x T1 / P1
What is the formula for Gay-Lussac?
Gay-Lussac's Law states that the pressure of a sample of gas at constant volume, is directly proportional to its temperature in Kelvin. The P's represent pressure, while the T's represent temperature in Kelvin. P1 / T1 = constant After the change in pressure and temperature, P2 / T2 = constant Combine the two equations: P1 / T1 = P2 / T2 When any three of the four quantities in the equation are known, the fourth can be calculated. For example, we've known P1, T1 and P2, the T2 can be: T2 = P2 x T1 / P1
What is the formula for gay lussacs law?
Gay-Lussac's Law states that the pressure of a sample of gas at constant volume, is directly proportional to its temperature in Kelvin. The P's represent pressure, while the T's represent temperature in Kelvin. P1 / T1 = constant After the change in pressure and temperature, P2 / T2 = constant Combine the two equations: P1 / T1 = P2 / T2 When any three of the four quantities in the equation are known, the fourth can be calculated. For example, we've known P1, T1 and P2, the T2 can be: T2 = P2 x T1 / P1
What is the relationship between density and temperature of CNG?
At low pressures you can use the ideal gas equation: (P1*V1)/T1 = (P2*V2)/T2 At constant volume, the equation will be: P1/T1 = P2/T2 At higher pressures (appr. above 10 bar) the deviation to real gas becomes significant, hence the compression factor (Z) is introduced.
Which of the following is not a valid equation for describing the behavior for gases?
(p1/v1) = (p2/v2)For Apex (P1 N1)= (P2N2 )
What does G2 P1 T1 mean in GYN?
In gynecology (GYN), G2 P1 T1 refers to a woman who has been pregnant twice (G2), had one live birth (P1), and one term birth (T1). This shorthand terminology is used to quickly convey a woman's obstetric history.
What is the final pressure of a 2.00 ATM gas container that increased in temperature from 299 K to 333 K while the volume increased from 650 mL to 850 mL?
P1 = 2T1 = 299T2 = 333V1 = 0.65V2 = 0.85P2t = P1 * T2 / T1 = 2.227 ATMP2v = P1 * V1 / V2 = 1.529 ATMP2 = P2t * P2v = 3.41 ATM
A sample of oxygen gas has a volume of 150 milliliters at 300k if the pressure of the sample is held constant and the temp raised to 600k the new sample will be?
Using the combined gas law (P1V1/T1 = P2V2/T2), we can calculate the new volume of the oxygen gas sample at 600K. Given P1V1/T1 = P2V2/T2, we have P1 = P2 (pressure is constant), V1 = 150 mL, T1 = 300K, and T2 = 600K. Plugging in these values, we get V2 = (P1 * V1 * T2) / (T1) = (1 * 150 * 600) / (300) = 300 mL. So, the new volume of the oxygen gas sample at 600K would be 300 milliliters.
The temperature of an ideal gas is directly proportional to?
the equation for an ideal gas is pv / t = nr n * r is a constant for a closed system p pressure v volume t temperature in kelvin p1 v1 /t1 = p2 v2 /t2 if p1 = p2 v1/t1 = v2/t2 t2= v2/v1 *t1 directly proportional to the change in volume if v1 = v2 the same can be done and you will find that t is directly proportional to change in pressure. generally t is directly proportional to the product of pressure and volume. pv = nr t
