V=IR
To calculate your voltage drop (V), you multiply your resistance (R, measured in Ohms) and current (I, measured in Amps [A]) by each other the. The number you are left with should be your voltage drop.
Electric power is not defined as current divided by voltage. Electric power (Watts) is equal to amps times voltage
A voltage of 13.8 kV is equal to 13,800 volts.
If you know the voltage you can calculate the amps. . Ampere I = power P / voltage V .
Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R
It depends on the type of three-phase system. If it's a three-wire system, then the phase voltage is numerically equal to the line voltage. If it's a four-wire system, then the phase voltage is numerically equal to the line voltage divided by 1.732 -in your example, this works out to be 5.77 V.
Power, in 'watts'.
Electric power is not defined as current divided by voltage. Electric power (Watts) is equal to amps times voltage
The voltage is greater than the applied voltage, why?
If you are referring to the voltage after the rectifiers in a powersupply, it is due to the voltage drop across the rectifiers.
The terminal voltage is equal to the supply voltage and there is zero current.
No. Voltage divided by resistance is equal to current.
By Kirchhoff's Voltage Law, the sum of the voltage drops around the series circuit will equal the voltage applied to the circuit.
Zero. The sum of the voltage drops across all loads plus the voltage rises due to sources in a complete circuit must equal zero.
The source voltage.
Less than or equal to 1KV comes under Low voltage.
The batteries can be connected in parallel or in series. In parallel, good batteries of the same voltage will have a total voltage across them equal to the voltage across one of them. Those batteries in series will have a total voltage equal to the sum of the voltage of each of the batteries.
Yes, in a series circuit, the sum of the voltage drops across each component equals the total voltage supplied by the voltage source. This principle is a manifestation of Kirchhoff's Voltage Law, which states that the total voltage around a closed loop must equal zero. Therefore, the voltage provided by the source must equal the combined voltage drops across all components in the circuit.