A carbonyl group is a carbon-oxygen double bond.
Yes, aldehyde is a structural isomer of a ketone. Both aldehydes and ketones contain a carbonyl group, but in aldehydes, the carbonyl group is located at the end of the carbon chain, while in ketones, it is located within the carbon chain.
CuSO4 isn't an element.
An element in group 1, such as sodium, will want to "hook up" with an element in group 17 (halogens) to form an ionic bond, gain a full outer shell, and become unreactive. Sodium will transfer an electron to the halogen to achieve a stable electron configuration.
Totally different compounds. Glycerol doesnt have any nitrogen whereas glycine does for example. Glycine is 1 of the 20 amino acids that make up proteins. look at them in wikipedia. Glycerol (C3H8O3) , glycine (C2H5NO2)
water
The carbonyl group consists of a carbon atom bonded to an oxygen atom by a double bond (C=O). It is a functional group found in various compounds such as aldehydes, ketones, carboxylic acids, and esters.
Example of elements forming carbonyls: Fe, Ni, Rh, Mn, Ti, Cr etc.
Carbon, Fluorine, and Oxygen
Yes, aldehyde is a structural isomer of a ketone. Both aldehydes and ketones contain a carbonyl group, but in aldehydes, the carbonyl group is located at the end of the carbon chain, while in ketones, it is located within the carbon chain.
Transition Metals
Nitrogen.
Oxygen is the element that makes up 78% of air and belongs to the 15th group in the periodic table.
No compounds make up elements. Elements make up compounds, so there are no compounds in cadmium since it is an element.
Calcium is an element, so calcium makes up calcium.
Acidic Conditions: Begin by protonating the oxygen in the carbonyl group, in the next step you can add water to the activated nucleophile to make the tetrahedral intermediate. The rest of the reaction are acid base reactions to maintain an acidic equilibrium and end up the ammonium as the acid catalyst. Basic Conditions: You may begin by adding the hydroxyl group to the carbonyl carbon and then protonating the now negative oxygen from the previous alkene with the proton left over by the hydroxyl group (originally it was water). You need to dissociate your tetrahedral intermediate by protonating the amide and then pushing it out when you take the proton by the oxygen pushing the electrons to make a double bond to form the carbonyl group and push out the NH3. In the end base deprotonates the carboxylic acid and you wind up with ammonium. The main key is equilibrium, you end up with a negative charged ion at the end because you maintain a negative charge in a basic mechanism.
element!