The chemical equation is:2 Al +3 CuCl2 = 3 Cu + 2 AlCl3
What do you think methane is if it isn't a chemical? The easiest way to get methane in a laboratory is to open the natural gas tap, since natural gas is mainly methane.
No, there should be no gas formed when mixing Drano and vinegar. The main ingredient in Drano is NaOH, and vinegar is acetic acid. So, the chemical reaction would be...NaOH + CH3COOH ==> CH3COONa + H2O. Neither is a gas.
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
The chemical equation is:2 Al(OH)3 = Al2O3 + 3 H2O
When you add CuCl2 to Al, a single displacement reaction occurs where Al replaces Cu in the compound to form AlCl3 and Cu. This reaction is typically exothermic and may result in the release of heat or even sparks due to the high reactivity of aluminum with copper chloride.
One product will be AlCl3 Copper metal will be a product
2Na + 2H2O = 2NaOH + H2 2Na + 2HCl = 2NaCl + H2 Na+H2O= NaOH2
CuCl2 and Al(s)
The chemical equation is:2 Al +3 CuCl2 = 3 Cu + 2 AlCl3
The balanced chemical equation for the reaction of aluminum (Al) with water (H2O) can be written as: 2Al(s) + 6H2O(l) → 2Al(OH)3(s) + 3H2(g).
The balanced chemical equation for the reaction of aluminum (Al) with water (H2O) to produce aluminum oxide (Al2O3) and hydrogen gas (H2) is: 4 Al + 3 H2O → 2 Al2O3 + 3 H2. From the balanced equation, we can see that 3 moles of water are needed for every 4 moles of aluminum reacting. Therefore, if 373 mol of aluminum is reacting, then (373 mol Al) x (3 mol H2O / 4 mol Al) = 279.75 mol of water would be produced.
Cu + HNO3 = CuNO3 + H2 or copper nitrate and hydrogen gasCu + 4 HNO3 --> Cu(NO3)2 + 2NO2 + 2H2OThe brown colored gas that comes of the reaction is NO2.
What do you think methane is if it isn't a chemical? The easiest way to get methane in a laboratory is to open the natural gas tap, since natural gas is mainly methane.
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Aluminum hydroxide is the chemical name for the molecular formula Al(OH)3. It is an ionic compound between Al 3+ and OH-. The equation for its disassociation in water is: Al(OH)3(s) + H2O(L) <--> Al 3+ (aq) + 3OH-(aq) + H2O (l).
The equation for the reaction of 1 mol of phosphoric acid (H3PO4) with 1 mol of aluminum hydroxide (Al(OH)3) is: 3H3PO4 + Al(OH)3 -> AlPO4 + 3H2O