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A mole of gas is equal to 6.02 x 1023 gas molecules.

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16y ago

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How many gas particles are one mole of gas?

There would be 6.022 x 1023 gas paricles in one mole of that gas.


What is the mass of 1 mole of gas?

39.95 because that is the molar mass of Argon


What does avogadros law say about a gas at STP?

1 mole of gas at STP occupies 22.4 liters.


What is constant for 1 mole of any ideal gas?

The Universal Gas Constant is 8.314 J/K/Mole


What is the mole fraction of oxygen gas in air?

The mole fraction of oxygen gas in air is approximately 0.21. This means that out of every 1 mole of air, 0.21 moles are oxygen gas molecules.


Which gas has the lowest mass per mole?

Hydrogen gas has the lowest mass per mole, with a molar mass of approximately 2 grams per mole.


How many moles of bromine atoms in 1 mole of bromine gas Chemistry question need help with homework?

one mole of a substance is described as 6.02x1023 atoms of a substance so if one mole of bromide gas contains 6.02x1023 atoms then bromide gas will contain one mole. your question is a trick question as the gas is stated as containg one mole there fore it contains one mole of bromide atoms


What ia CNG?

Compressed natural gas


What is the volume of a mole of any gas at standard temperature and pressure?

The volume of a mole of any gas at Standard Temperature and Pressure (STP) is approximately 22.4 liters. This is known as the molar volume of a gas at STP and is a standard value used in gas calculations.


What is the constant for 1 mole of any ideal gas?

The Universal Gas Constant is 8.314 J/K/Mole


One mole of N2 gas at STP will occupy what volume?

22.4 L. At STP 1 mole of any gas will always be equal to 22.4 L.


If 1 mole of gas occupies 224 dm cubed then how many m cubed would 2263000 tons be?

There is one critical piece of information missing in the question, i.e. which gas are we talking about since different gas will have different molecular weight. In addition 1 mole of gas occupies volume of 22.4 dm3 at stp. This is equivalent to 22.4 L or 0.0224 m3 per mole of gas. Assuming the molecular weight of the gas Y is x g/mole, then the general solution is as followed: 2263000 tons of gas Y equal 226300*1016*1000g/(x g/mole)*(0.0224 m3/mole) equal 5.15022592e9/x m3 of gas Y