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I'm guessing you meant sickle cell anemia. You already said that it's recessive, which means that both parents have to be carriers for it to be passed on to their children. If both parents carry the gene, then there is a 1 in 4 chance of having an affected offspring, 2 in 4 chances of having offsprings which carry the disease, and 1 in 4 of the child being unaffected (check out how to draw a punnet square). If one parent is a carrier and the other one is healthy, then you have a 50% chance of having an offspring who carries the disease, but none of your offsprings will be affected. Hope this helps
What else can I help you with?
If Tall is dominant over short a homozygous dominant man marries a homozygous recessive woman what of their children are expected to be short?
All of their children are expected to be heterozygous for the trait (Tt), which means they would be tall (dominant phenotype). The recessive trait for being short would only manifest if both copies of the gene were recessive.
In a dyhibrid cross the expected porportion of offspring showing both recessive traits is?
The expected proportion of offspring showing both recessive traits in a dihybrid cross is 1/16 or 6.25%. This is because each trait segregates independently and the probability of both recessive traits occurring together is the product of the individual probabilities (1/4 x 1/4 = 1/16).
Color blindness is an X-linked recessive trait A color-blind man has a daughter with normal color vision She mates with a male who has normal color vision What is the expected phenotypic ratio of t?
The expected phenotypic ratio for their offspring is 1:1, with a 50% chance of being color blind (male with the X-linked recessive trait) and a 50% chance of having normal color vision. This is because the daughter is a carrier of the recessive allele, which can be passed on to her offspring regardless of the father's color vision status.
What is the genotypic ratio for a tetrahybrid cross?
1:1:1:1:1:1:1:1 ratio is the expected outcome of a heterozygous (BbGgCc) and a homozygous recessive (bbggcc) cross.
Why does the expected genotype ratio often differ from expected phenotype ratio from a monohybrid cross?
This would be because phenotypes are the observable characteristics whilst genotypes are the actual genes. If we are given the genes: R (dominant) and r (recessive), and 2 organisms with Rr genes (one dominant and one recessive) produce offspring, their offspring will have one of the following genes, with the percentage chance in brackets: RR (25%) Rr (50%) rr (25%) However, you can't detect recessive genes if a dominant gene is present, thus there will be no observable difference between the RR and Rr organism, besides for their offspring. Thus, the phenotype is 75% and 25%, unlike for the genotype.
If Tall is dominant over short a homozygous dominant man marries a homozygous recessive woman what of their children are expected to be short?
All of their children are expected to be heterozygous for the trait (Tt), which means they would be tall (dominant phenotype). The recessive trait for being short would only manifest if both copies of the gene were recessive.
If the population of a country has a larger proportion of children than of adults then the population can be expected to?
Grow in size.
In a dyhibrid cross the expected porportion of offspring showing both recessive traits is?
The expected proportion of offspring showing both recessive traits in a dihybrid cross is 1/16 or 6.25%. This is because each trait segregates independently and the probability of both recessive traits occurring together is the product of the individual probabilities (1/4 x 1/4 = 1/16).
In a dominant characteristic a man who does not have a chin dimple has children with a woman with a chin dimple. What proportion of their children would be expected to have a chin dimple?
50% would be expected to have the dimple, but in the pot shoot that makes up our genetic material, all or none may in reality end up dimpled.
What can be expected for the recessive trait of monohybrid from the f2 generation?
your mom, your dad
If you throw exactly two heads in two tosses of a coin you win 81 dollars if notyou pay 24 dollars what is the expected value of proportion?
The answer depends on what proportion you want the expected value for.
What is the expected frequency for a person to have all six recessive characteristic?
The expected frequency for a person to have all six recessive characteristics would be very low, as it would require inheriting two recessive alleles for each of the six traits. This would be a rare occurrence due to the probability of inheriting multiple recessive alleles for each trait from both parents.
The expected frequency is determined by multiplying the sample size by the hypothesized proportion?
True.
What is the expected genotypic ratios for di-hybrid cross and mono-hybrid cross?
In a dihybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively. In a monohybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively.
What were the evacuees expected to do at there new schools?
They were expected to do what children in schools everywhere do - learn.
What can be expected for the recessive trait of monohybrids from the F2 generation?
In the F2 generation of monohybrids, the recessive trait can reappear in a ratio of 3:1 along with the dominant trait. This is because recessive traits can be masked in the F1 generation but resurface in the F2 generation due to genetic segregation.
Out of 200 offspring of heterozygous brown rabbits and white rabbits how many white rabbits would be expected?
Half of the offspring, or 100 rabbits, would be expected to be white when offspring from a heterozygous brown rabbit and a white rabbit are produced. This is due to the dominant-recessive inheritance pattern where brown is dominant and white is recessive.
