the intermolecular forces present in methanol are hydrogen bond between the oxygen and hydrogen part of the molecule and van der waals forces between the carbon and hydrogen part of the molecule.
London or vanderwal force
The intermolecular forces are hydrogen bonding.
No, strong intermolecular forces typically have negative values when expressed numerically in terms of energy or potential energy. The more negative the value, the stronger the intermolecular forces.
London dispersion forces
Cu has a lower boiling point than CH3OH because its particles are less polar. the CH3OH molecules have to have more kinetic energy to break the bonds between them and the surrounding molecules.
Keesom forces Debeye forces London forces And H-bonding
NaOH has the higher melting point. The reason is since NaOH is an ionic compound, thus meaning that the intermolecular forces (the forces that hold the compound together) between Sodium+ and Hydroxide- are ionic - ionic forces. The charges keep them together. Ionic forces are ALOT stronger than other intermolecular forces such as dispersion, dipole-dipole, or even hydrogen bonding. CH3OH (Methanol) has a lower melting point that Sodium Hydroxide since the intermolecular forces it entails are: Dispersion, dipole-dipole, and hydrogen bonding between Hydrogen and Oxygen. It will take LESS energy to break these attractions, than the energy required to break the attraction forces between the ionic compound NaOH.
The relative strength of intermolecular forces depends on the types of molecules involved. Compounds with hydrogen bonding, such as water, tend to have stronger intermolecular forces compared to those with only London dispersion forces, like diethyl ether. This results in higher boiling points for compounds with stronger intermolecular forces.
Oxygen (O2) would be expected to behave more ideally at high pressures compared to methanol (CH3OH). This is because oxygen is a diatomic gas with weak intermolecular forces, making it behave closer to an ideal gas at high pressures. Methanol, on the other hand, is a polar molecule with stronger intermolecular forces, which can cause deviations from ideal behavior.
Methanol (CH3OH) has stronger intermolecular forces due to hydrogen bonding, leading to a higher boiling point compared to methanethiol (CH3SH), which only experiences weaker dispersion forces. Hydrogen bonding involves a stronger dipole-dipole attraction between the molecules of methanol, requiring more energy to overcome compared to the dispersion forces in methanethiol molecules.
If you mean CH3OH, then the strongest intermolecular force is hydrogen bonding as this is an alcohol containing and OH group. There are other other forcs such a sLondon dispersion forces but these are weaker as CH3OH doesn't have many electrons.
Factors affecting intermolecular forces include the type of molecules involved (polar or nonpolar), the size and shape of the molecules, and the presence of any hydrogen bonding or dipole-dipole interactions. Temperature and pressure can also impact intermolecular forces.
Intramolecular forces are not intermolecular forces !
London or vanderwal force
Ok let's look at the different molecules: 1. CH3COCH3 is acetone. The molecule is a trigonal planar around the central carbon with the electronegative oxygen pulling electron density towards itself. So this is a polar molecule. 2. O2 is non-polar and relies only on dispersion forces. 3. CH3OH is has hydrogen bonding, dipole-dipole forces, and dispersion forces. 4. SO3 is a trigonal planar molecule with three oxygens around the sulfur, making it non-polar. Therefore it relies only on dispersion forces. 5. H2S is another polar molecule (bent by two lone pairs on the sulfur). So SO3 and O2 are the two molecules relying mainly on dispersion (London) forces.
The intermolecular forces are hydrogen bonding.
When there is more thermal energy, then there are less intermolecular forces.