To simplify the expression -5p³(4p² + 3p¹), distribute -5p³ to both terms inside the parentheses. This results in -5p³ * 4p² = -20p^(3+2) = -20p⁵ and -5p³ * 3p¹ = -15p^(3+1) = -15p⁴. Therefore, the final expression is -20p⁵ - 15p⁴.
The "ne" in ne3s2 3p1 refers to the element Neon, which is a chemical element with the atomic number 10. The notation ne3s2 3p1 specifies the electron configuration of Neon, where the "ne3s2" denotes 3 electrons in the 3s orbital and "3p1" denotes 1 electron in the 3p orbital.
Two aluminum atoms and three sulfur atoms are combined in the compound aluminum sulfide (2 Al + 3 S = Al2S3).
1s2, 2s2 2p6, 3s2 3p1or[Ne], 3s2 3p1
[Ne] 3s2 3p1
1s2 2s2 2p6 3s2 3p1
The "ne" in ne3s2 3p1 refers to the element Neon, which is a chemical element with the atomic number 10. The notation ne3s2 3p1 specifies the electron configuration of Neon, where the "ne3s2" denotes 3 electrons in the 3s orbital and "3p1" denotes 1 electron in the 3p orbital.
The 3p1 electron configuration belongs to phosphorus with the electron configuration 1s2 2s2 2p6 3s2 3p1. This means that phosphorus has 15 electrons, with the last electron occupying the 3p subshell.
Two aluminum atoms and three sulfur atoms are combined in the compound aluminum sulfide (2 Al + 3 S = Al2S3).
1s2, 2s2 2p6, 3s2 3p1or[Ne], 3s2 3p1
[Ne] 3s2 3p1
(Ne) 3S2 3P1
[Ne] 3s2 3p1
[Ne] 3s2 3p1
1s2 2s2 2p6 3s2 3p1
1s2 2s2 2p6 3s2 3p1
The electron configuration of aluminum is 1s2 2s2 2p6 3s2 3p1. This means aluminum has 13 electrons in total, with two in the first energy level, eight in the second energy level, and three in the third energy level.
In the electron configuration of aluminum, the 3p1 electron corresponds to the 3rd energy level (n=3) and is in the p subshell. The second quantum number, also known as the azimuthal quantum number (l), for a p subshell is 1. Therefore, the second quantum number of the 3p1 electron in aluminum is l = 1.