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To convert moles of magnesium carbonate (MgCO₃) to formula units, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) formula units per mole. Therefore, 1.72 moles of magnesium carbonate is calculated as follows:
[ 1.72 , \text{moles} \times 6.022 \times 10^{23} , \text{formula units/mole} \approx 1.034 \times 10^{24} , \text{formula units}. ]
Thus, 1.72 moles of magnesium carbonate is approximately (1.034 \times 10^{24}) formula units.
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Determine the number of formula units that are in 0.688 moles of AgNO3?
0.688 moles*6.02x1023=4.14x1023 Formula units
How many formula units make up 10.6 g of magnesium chloride?
To find the number of formula units in 10.6 g of magnesium chloride (MgCl₂), first calculate its molar mass. The molar mass of MgCl₂ is approximately 95.21 g/mol. Then, convert grams to moles: (10.6 , \text{g} \div 95.21 , \text{g/mol} \approx 0.111 , \text{mol}). Finally, multiply the moles by Avogadro's number ((6.022 \times 10^{23}) units/mol) to get the number of formula units: (0.111 , \text{mol} \times 6.022 \times 10^{23} \approx 6.69 \times 10^{22}) formula units of magnesium chloride.
How many formula units make up 10.4 g of magnesium chloride?
To find the number of formula units in 10.4 g of magnesium chloride (MgCl₂), first calculate its molar mass: Mg (24.31 g/mol) + 2 × Cl (35.45 g/mol) = 95.21 g/mol. Next, determine the number of moles in 10.4 g: 10.4 g ÷ 95.21 g/mol ≈ 0.109 moles. Since one formula unit of MgCl₂ corresponds to one mole of the compound, you can find the number of formula units by multiplying the moles by Avogadro's number (approximately (6.022 \times 10^{23})): 0.109 moles × (6.022 \times 10^{23}) ≈ (6.56 \times 10^{22}) formula units.
How many formula units of salt make up 10 moles?
10 formula units
How many formula units make up 21.8 g of magnesium chloride (MgCl2)?
To find the number of formula units in 21.8 g of magnesium chloride (MgCl₂), first calculate its molar mass. The molar mass of MgCl₂ is approximately 95.3 g/mol (24.3 g/mol for Mg and 35.5 g/mol for Cl, multiplied by 2). Next, divide the mass of MgCl₂ by its molar mass: 21.8 g ÷ 95.3 g/mol ≈ 0.229 moles. Finally, multiply the number of moles by Avogadro's number (6.022 × 10²³) to find the number of formula units: 0.229 moles × 6.022 × 10²³ ≈ 1.38 × 10²³ formula units.
What is the number of formula units that are in 5.68 moles of magnesium oxide?
To find the number of formula units of magnesium oxide in 5.68 moles, you first need to determine the formula of magnesium oxide (MgO). Then use Avogadro's number (6.022 x 10^23) to convert moles to formula units. So, in 5.68 moles of MgO, there are approximately 3.43 x 10^24 formula units.
How many formula units are there in 2.5 grams of Magnesium Chloride?
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
How many moles of ammonium ions are in 8.903 g of ammonium carbonate?
The most common form of solid ammonium carbonate is a hydrate with formula (NH4)2CO3.H2O and a gram formula unit mass of 114.10. The formula shows that each formula unit contains 2 ammonium ions. The number of formula units of ammonium carbonate is 8.903/114.10 or 0.078028. The number of formula units of ammonium ions is twice this, or 0.1561, to the justified number of significant digits.
How many formula units make up 33.8 g of magnesium chloride (MgCl2)?
To find the number of formula units in 33.8g of magnesium chloride (MgCl2), you first need to calculate the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 g/mol. Then, divide the given mass by the molar mass to find the number of moles, which is 0.355 moles. Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of formula units.
How many formula units make up 25.2 g of magnesium chloride?
To determine the number of formula units, you need to first calculate the molar mass of magnesium chloride (MgCl2). The molar mass is 95.21 g/mol. Next, divide the given mass (25.2 g) by the molar mass to find the number of moles of magnesium chloride. Finally, use Avogadro's number (6.022 x 10^23) to convert moles to formula units.
How many formula units make up 12.2g of magnesium chloride?
To determine the number of formula units in 12.2g of magnesium chloride, you need to first calculate the molar mass of magnesium chloride (MgCl2). The molar mass of MgCl2 is 95.21 g/mol. Next, divide the given mass (12.2g) by the molar mass of MgCl2 to find the number of moles present. Finally, use Avogadro's number (6.022 x 10^23) to convert moles to formula units.
How many formula units make up 25.6 g of magnesium chloride (MgCl2)?
To find the number of formula units in 25.6 g of magnesium chloride (MgCl2), first calculate the molar mass of MgCl2 (95.21 g/mol). Then divide the given mass by the molar mass to find the number of moles (0.269 mol). Finally, use Avogadro's number (6.022 x 10^23 units/mol) to convert moles to formula units, resulting in approximately 1.62 × 10^23 formula units in 25.6 g of MgCl2.
Determine the number of formula units that are in 0.688 moles of AgNO3?
0.688 moles*6.02x1023=4.14x1023 Formula units
How many formula units does 200 grams of Calcium Carbonate represent?
Well, darling, to find the number of formula units in 200 grams of Calcium Carbonate, you first need to calculate the molar mass of CaCO3. Once you do the math, you'll find that one mole of CaCO3 weighs 100.09 grams. So, 200 grams of CaCO3 represents 2 moles of the compound, which is equivalent to 2 times Avogadro's number (6.022 x 10^23) formula units. Voilà!
How many formula units make up 32.2 g of magnesium chloride (MgCl2)?
To determine the number of formula units in 32.2 g of magnesium chloride (MgCl2), you need to first calculate the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 g/mol. Then, divide the given mass by the molar mass to find the number of moles, and finally, use Avogadro's number (6.022 × 10^23) to convert moles to formula units.
How many formula units make up 10.6 g of magnesium chloride?
To find the number of formula units in 10.6 g of magnesium chloride (MgCl₂), first calculate its molar mass. The molar mass of MgCl₂ is approximately 95.21 g/mol. Then, convert grams to moles: (10.6 , \text{g} \div 95.21 , \text{g/mol} \approx 0.111 , \text{mol}). Finally, multiply the moles by Avogadro's number ((6.022 \times 10^{23}) units/mol) to get the number of formula units: (0.111 , \text{mol} \times 6.022 \times 10^{23} \approx 6.69 \times 10^{22}) formula units of magnesium chloride.
How many formula units make up 32.0 g of magnesium chloride (MgCl2)?
To find the number of formula units in 32.0 g of magnesium chloride (MgCl2), you first need to calculate the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 g/mol. Next, divide the given mass by the molar mass to get the number of moles, and then use Avogadro's number to convert moles to formula units. So, 32.0 g / 95.21 g/mol ≈ 0.336 moles of MgCl2, and then using Avogadro's number, this corresponds to approximately 2.02 x 10^23 formula units of MgCl2.
