I would tell, no reaction will occur the way the question has been asked.
The H-C bond and each C-Cl bond are covalent bonds.
The S-Cl bond is polar. The electronegativity difference between S and Cl is 0.58, which means it is polar.
Three - C = carbon H = hydrogen Cl = chlorine
1 that's the answer
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
It contains Cl,C,H atoms. C,Cl2,H2 are the sources.
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
cl / H - C - cl / cl
To draw the Lewis structure for CH2Cl2, start by calculating the total number of valence electrons (4 for C, 1 for H, 7 for Cl). Place the least electronegative atom in the center (C). Connect H and Cl to C with single bonds. Place lone pairs on Cl to satisfy the octet rule. Double check that all atoms have a full octet.
the difference is that in pvc h-c is replaced with c-cl. c-cl is less oxidisible by air while h-cl is oxidisable hence flamable while cl-c doesn't
H2 + Cl2 --> 2HCl
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
i think its 2NaOH + Cl2 ------------> NaClO + NaCl + H2O i think
It is already balanced, you have the same number of H's and the same number of Cl's in each side of the equation.
H2 + Cl2 --> 2HCl Think of it like this. H2 begins with two electrons, Cl2 begins with 14 (it is diatomic and originally has 7 electrons, so 7 + 7 = 14). The reducing agent is the one being oxidized (you need to remember that!) and if something is being oxidized, it is going from having more electrons to less electrons. 2HCl has 16 electrons (where H has two and Cl has fourteen), so, unless there is a charge on any of these compounds that you did not include in your question, no, Cl is not the reducing agent.
Hydrogen , H2 ( H-H) Chlorine , Cl2 ( Cl - Cl). However, NOT oxygen , it is doubly bonded , O2 ( O=O). Nor nitrogen , which is triply bonded , N2 ( N///N)