The Cl₂ molecule consists of two chlorine atoms, each contributing seven valence electrons. In a Lewis dot structure, each chlorine atom is represented by its chemical symbol (Cl) surrounded by seven dots, indicating its valence electrons. When the two chlorine atoms bond to form Cl₂, they share one pair of electrons, resulting in a single covalent bond. The Lewis dot structure for Cl₂ shows two Cl symbols connected by a line (representing the bond) and each atom still having six remaining dots around it, which represent the unshared valence electrons.
If the concentration of Cl2 is decreased, the reaction will shift to the left to try to replace the lost Cl2. This means more C2H4 will react with any remaining Cl2 to form more C2H4Cl2 until a new equilibrium is reached with a lower concentration of Cl2.
The balanced equation for the reaction between sodium (Na) and chlorine (Cl2) to form sodium chloride (NaCl) is 2Na + Cl2 -> 2NaCl. This equation is balanced because it has an equal number of each type of atom on both sides of the reaction arrow.
To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.
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in the reaction of H2 and Cl2 hydrogen is oxidised. Chlorine is reduced.
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Cl2 is non polar.So there are london bonds.
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You start with methane (CH4 ) and chlorine ( Cl2) and react them thus:- CH4 + Cl2 → CH3Cl + HCl CH3Cl + Cl2 → CH2Cl2 + HCl CH2Cl2 + Cl2 → CHCl3 + HCl
If the concentration of Cl2 is decreased, the reaction will shift to the left to try to replace the lost Cl2. This means more C2H4 will react with any remaining Cl2 to form more C2H4Cl2 until a new equilibrium is reached with a lower concentration of Cl2.
The balanced equation for the reaction between sodium (Na) and chlorine (Cl2) to form sodium chloride (NaCl) is 2Na + Cl2 -> 2NaCl. This equation is balanced because it has an equal number of each type of atom on both sides of the reaction arrow.
2K + Cl2 --> 2KCl
To find the number of moles of Cl2 in 7.1g of chlorine, you need to divide the mass of Cl2 by its molar mass. The molar mass of Cl2 is 70.9 g/mol. Therefore, 7.1g / 70.9 g/mol = 0.1 moles of Cl2.
The balanced equation for the reaction between calcium (Ca) and chlorine (Cl2) to form calcium chloride (CaCl2) is: 2Ca + Cl2 -> 2CaCl2