The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).
R R r Rr Rr r Rr Rr That is the Punnet Square. The genotype will be 100% Rr in the cross. The phenotype will be whatever phenotype is constituted by your dominant allele.
simple Mendelian genetics...right-handed is the dominant allele (R), left-handed is recessive (r). you can figure it out using a Punnett square. RR, Rr = RH kid rr = LH kid RR + RR = 100% RR -> all RH kids RR + Rr = 50% RR, 50% Rr -> all RH kids Rr + Rr = 25% RR, 50% Rr, 25% rr -> 75% RH kids, 25% LH kids rr + rr = 100% rr -> all LH kids to be LH, you have to have left-handedness somwhere in the family. however, you can be LH and neither your parents or grandparents would have to be.
RR Donnelley was created in 1864.
The word "sufferer" has both "ff" and "rr" in it.
The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).
When crossing two heterozygous red flowers (Rr), you would use a Punnett square to determine the possible genotypes and phenotypes of the offspring. In this case, the genotypes of the parents are Rr x Rr. The possible offspring genotypes would be RR, Rr, and rr, with a phenotypic ratio of 1 red : 2 pink : 1 white flower.
using a punnett square the parents would have to be Rr and rr
RR X rr 100% Rr Heterozygous resistant for poison ivy.
To figure this out, use a Punnet Square.First, set up a test cross, like this:Rr x rrThis shows what you are crossing. Now you can make a Punnet Square.R rr Rr rr There is a 50/50 chance that the corn plant will have thegenotype rr.r Rr rr
If they are expressing the trait, 100%, as their genotypes would be, rr X rr If they both carry the trait and it is dominated, Rr X Rr, then the probability would be, 25% of their child expressing the trait.
The resulting generation will have a 1:1 ratio of RR to rr genotypes when crossing an Rr genotype with a rr genotype, as each parent will contribute one allele to the offspring.
Rr x Rr is an example of a monohybrid cross, specifically a cross between two heterozygous individuals for a single trait. This type of cross helps determine the possible genotypic and phenotypic outcomes for the offspring.
The recessive trait is represented by the genotype rr, where both alleles are lowercase. The genotype RR represents the dominant trait.
R R r Rr Rr r Rr Rr That is the Punnet Square. The genotype will be 100% Rr in the cross. The phenotype will be whatever phenotype is constituted by your dominant allele.
This is the deck. Please put your answer underneath! Pokémon Staryu Rising Rivals x3 Starmie RR x 2 Snorunt Arceus x2 Froslass A x1 Wingull A x2 Pelipper A x1 Rhyperior E4 RR x1 Aerodactyl GL RR x1 Hippopotas RR x3 Hippowdon RR x1 Trapinch RR x3 Vibrava RR x2 Flygon RR x1 Energy Water Energy x12 Fighting Energy x12 Trainers Potion Stormfront x2 Switch Stormfront x2 Felicity's Drawing Great Encounters x2 Bebe's Search RR x2 Volkner's Philosophy RR x1 Aaron's Collection RR x1 Bertha's Warmth RR x1 Flint's Willpower RR x1
simple Mendelian genetics...right-handed is the dominant allele (R), left-handed is recessive (r). you can figure it out using a Punnett square. RR, Rr = RH kid rr = LH kid RR + RR = 100% RR -> all RH kids RR + Rr = 50% RR, 50% Rr -> all RH kids Rr + Rr = 25% RR, 50% Rr, 25% rr -> 75% RH kids, 25% LH kids rr + rr = 100% rr -> all LH kids to be LH, you have to have left-handedness somwhere in the family. however, you can be LH and neither your parents or grandparents would have to be.