The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
The reaction between selenium dioxide and aqueous potassium hydroxide forms selenites, or salts containing the SeO3^2- ion, and water. This reaction can be represented as SeO2 + 2KOH + H2O → K2SeO3 + H2O.
CaCO3(s) + 2HCl(aq) -> CaCl2(aq) + H2CO3(aq) is the balanced chemical equation H2CO3 is not stable in this form, so it splits into CO2(g) + H2O(l) Therefore the true equation will be: CaCO2(s) + 2HCl(aq) -> CaCl2(aq) + CO2(g) + H2O(l) You NIE will start like this: CaCO2(s) + 2H+(aq) + 2Cl-(aq) -> Ca2+(aq) + 2Cl-(aq) + CO2(g) + H2O(l) and will end as: 2H+(aq) + CaCO2(s) -> Ca2+(aq) + CO2(g) + H2O(l)
This is not a decomposition reaction.
Kb=[(Ch3)3 NH+][OH-] __________ [(Ch3)3 N]
The Kb for (CH3)3N (trimethylamine) in water is a measure of the strength of the base (CH3)3NH in solution. It is used to calculate the equilibrium concentration of hydroxide ions (OH-) in solution when the base dissociates.
KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l)
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) -> H2O(l) + Na+(aq) + Cl-(aq)
Na+ + OH- + H+ + Cl- H2O + Na+ + Cl-
HClO4(aq) + NaOH(aq) → H2O(l) + NaClO4(aq) Ionic Equation: H+ + ClO4- + Na+ + OH- → H2O + Na+ + ClO4-
H+(aq)+OH−(aq)→H2O(l)
HNO3 (aq) + NaOH (aq) --> H2O (l) + NaNO3 (aq)
Overall ionic equation: K+(aq) +OH-(aq)+ H30+(aq) + Cl-(aq)------>2H20 (l) + K+(aq) + Cl-(aq) Net ionic Equation OH-(aq)+ H30+(aq) ------>2H20 (l)
H^+(aq) + C2H3O2^-(aq) + Na^+(aq) + OH^-(aq) = Na^+(aq) + C2H3O2^-(aq) + H2O(L)Reducing (by crossing out repeated [spectator] ions) gives H^+(aq) + OH^-(aq) = H2O(L)
Equilibrium:NO2- (aq) + H2O HNO2 (aq) + OH- (aq)
The equation is:H+ + (NO3)- + Na+ + (OH)- = (NO3)- + Na+ + H2O (2 H+ OH-)